mid3 58010 Fall14-solutions - Version 064 mid3 58010 Fall14...

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Version 064 – mid3 58010 Fall14 – yeazell – (58010)1Thisprint-outshouldhave9questions.Multiple-choice questions may continue onthe next column or page – find all choicesbefore answering.00110.0pointsIn a seriesRLCAC circuit, the resistance is33 Ω, the inductance is 28 mH, and the capac-itance is 19μF.The maximum potential is235 V, and the angular frequency is 100 rad/s.Calculate the maximum current in the cir-cuit.1. 0.4479992. 0.2484653. 0.2048344. 0.1401065. 0.5626436. 0.04700227. 0.1866518. 0.3569559. 0.15916610. 0.124679NWhat is the direction of the induced currentin the loop before it passes through the wire(viewed from top)? After it passes through?Correct answer: 0.447999 A.Explanation:Let :R= 33 Ω,L= 28 mH = 0.028 H,C= 19μF = 1.9×105F,Vmax= 235 V,andω= 100 rad/s.The capacitive reactance isXC=1ω C=1(100 rad/s) (1.9×105F)= 526.316 Ωand the inductive reactance isXL=ω L= (100 rad/s) (0.028 H)= 2.8 Ω,so the maximum current isImax=VmaxZ=VmaxradicalbigR2+ (XLXC)2=235 Vradicalbig(33 Ω)2+ (2.8 Ω526.316 Ω)2=0.447999 A.1.Unable to determine2.no induced current3.clockwise; clockwise4.counterclockwise; clockwisecorrect5.counterclockwise; counterclockwise6.clockwise; counterclockwiseExplanation:Before the bar magnet passes through thewire, the magnetic field points downward andis increasing, so the induced current wouldcreate a magnetic field directed upward. Thedirection of the induced current should becounterclockwise.After the bar magnet passes through thewire, the magnetic field points downward and00210.0pointsA bar magnet is dropped, north pole down, sothat it falls through a circular piece of wire,as shown.S

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