ch10 - CHAPTER 10 SOLUTIONS 10.1 a. Minimum utilities, Tmin...

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10-1 CHAPTER 10 SOLUTIONS 10.1 a. Minimum utilities, T min = 10 ° C Process Stream T s , ° C T t , ° C C , KW/ ° C H1 180 60 3 H2 150 30 1 C1 30 135 2 C2 30 140 5 Adjusted temperatures Adjusted T s , ° C T t , ° C T s , ° C T t , ° C H1 180 170 T o 60 50 T 4 H2 150 140 T 1 30 20 T 6 C1 30 30 T 5 135 135 T 2 C2 80 80 T 3 140 140 Interval heat balances Energy Flows Between Intervals Initial Pass Q steam = 0 R 1 = 90 R 2 = 85 R 3 = -80 R 4 = -20 R 5 = -40 Q cw = -30 Final Pass 80 170 165 0 60 40 50 Q steam H 1 = 90KW R 1 H 2 = -5KW R 2 H 3 = -165KW R 3 H 4 = 60KW R 4 H 5 = -20KW R 5 H 6 = 10KW Q cw T o = 170°C — T 1 = 140°C — T 2 = 135°C — T 3 = 80°C — T 4 = 50°C — T 5 = 30°C — T 6 = 20°C — Pinch The pinch temperatures are 80 ° C (cold streams) and 90 ° C (hot streams).
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10-2
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10-3 b. Heat exchanger network for minimum utilities C, KW/C 3 H1 1 H2 2 C1 5C 2 P i n c h 180 ° C 90 ° C9 0 ° C6 0 ° C 150 ° C 90 ° 0 ° C8 0 ° C cw 30 ° C 50KW 135 ° Cs1 1 0 ° C 80 ° 0 ° C3 5 ° 0 ° C 50 KW 60KW 90KW 10KW 140 ° 3 4 ° C 80 ° C 30 KW 270KW
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10-4 10.2 a. Minimum utilities, T min = 10 ° C Process Stream T s , ° C T t , ° C C , KW/ ° C Q , KW C1 60 180 3 360 C2 30 105 2.6 195 H1 180 40 2 280 H2 150 40 4 440 Adjusted temperatures Adjusted T s , ° C T t , ° C T s , ° C T t , ° C C1 60 60 T 4 180 180 T o C2 30 30 T 5 105 105 T 3 H1 180 170 T 1 40 30 H2 150 140 T 2 40 30 Interval heat balances Energy Flows Between Intervals Initial Pass Q steam = 0 R 1 = -30 R 2 = -60 R 3 = 45 R 4 = 63 Q cw = 165 Final Pass 60 30 0 105 123 225 Q steam H 1 = -30KW R 1 H 2 = -30KW R 2 H 3 = 105KW R 3 H 4 = 18KW R 4 H 5 = 102KW Q cw T o = 180°C — T 1 = 170°C — T 2 = 140°C — T 3 = 105°C — T 4 = 60°C — T 5 = 30°C — Pinch
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10-5
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10-6 b. Minimum utilities, T min = 10 ° C Process Stream T s , ° C T t , ° C C , KW/ ° C C1 100 430 1.6 C2 180 350 3.27 C3 200 400 2.6 H1 440 150 2.8 H2 520 300 2.38 H3 390 150 3.36 Adjusted temperatures Adjusted T s , ° C T t , ° C T s , ° C T t , ° C C1 100 100 T 9 430 430 C2 180 180 T 7 350 350 T 4 C3 200 200 T 6 400 400 T 2 H1 440 430 T 1 150 140 T 8 H2 520 510 T o 300 290 T 5 H3 390 380 T 3 150 140 Interval heat balances Energy Flow Between Intervals Initial Pass Q steam = 0 R 1 = 190.4 R 2 = 297.8 R 3 = 317.4 R 4 = 447.6 R 5 = 511.8 R 6 = 393.9 R 7 = 419.7 R 8 = 602.1 Q cw = 538.1 Q steam H 1 = 190.4 kW/ o C R 1 H 2 = 107.4 R 2 H 3 = 19.6 R 3 H 4 = 130.2 R 4 H 5 = 64.2 R 5 H 6 = -117.9 R 6 H 7 = 25.8 R 7 H 7 = 182.4 R 8 H 5 = -64 Q cw T o = 510 o C — T 1 = 430 o C — T 2 = 400 o C — T 3 = 380 o C — T 4 = 350 o C — T 5 = 290 o C — T 6 = 200? o C— T 7 = 180 o C — T 8 = 140 o C — T 9 = 100 o C —
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10-7 c. a. s cw 30°C 60°C 40°C 25KW 200KW 195KW 90°C 2 240KW 60KW 60KW 105°C 140°C 150°C 140°C 160°C 180°C 1 C 3 2 40°C 52.5°C 3 1 150°C Pinch 150°C 180°C H1 H2 C1 C2 2 4 3 2.6 C , KW/°C C2 cw cw 25 KW 195 KW 200 KW 60 KW 60 KW 240 KW 105 ° C 52.5 ° C 30 ° C 150 ° C 90 ° C 180 ° C 160 ° C 180 ° C 150 ° C 60 ° C 140 ° C 3 H 1 C 2 C1 H1 H2 C 40 ° C 40 ° C steam
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10-8 b. C1 H3 H1 H2 440 ° C C , KW/ o C 150 ° C 3.6 254.1 cw 520 283.9 cw 181.1 ° C 528 225.6 ° C 301.5 ° C 400 ° C 350 ° C 430 ° C 390 ° C 4 2 1 3 3 4 2 1 520 ° C 251.4 ° C 552.3 300 ° C 150 ° C 100 ° C 180 ° C 200 ° C 2.8 2.38 3.36 1.6 3.27 2.6 Pinch C2 C3 430 ° C 254.1 kW 150 ° C 350 ° C 225.6 ° C 181.1 ° C CW 301.5 ° C 1 3 2 4 300 ° C CW 150 ° C 283.9 kW H3 390 ° C H1 440 ° C H2 520 ° C C1 100 ° C C3 200 ° C C2 180 ° C 400 ° C 251.4 ° C
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10-9 10.3 Minimum utilities, T min = 20 ° C Process Stream T s , ° C T t , ° C C , KW/ ° C C1 20 125 2.5 C2 25 100 3.0
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This note was uploaded on 04/10/2008 for the course CHE 233W taught by Professor Debelak during the Spring '08 term at Vanderbilt.

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ch10 - CHAPTER 10 SOLUTIONS 10.1 a. Minimum utilities, Tmin...

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