1036 HW 1 _sol_

1036 HW 1 _sol_ - General Chemistry 1036 Homework 1...

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General Chemistry 1036 Homework 1 Solutions 1. The metal with a higher heat capacity undergoes the smallest change in temperature. Copper has a higher specific heat value compare to silver and thus, it undergoes the smallest change in temperature with mass and amount of heat being equal. 2. q = m * c * Δ t q = 8.35 kJ = 8350 J m = 112 g c = 1.74 J.g -1 .°C -1 Δ t = t final – t initial = t final – 20.0°C 8350 J = 112 g * 1.74 J.g -1 . o C -1 * (t final – 20.0°C) t - 20.0 C = 8350 J 112 g * 1.74 J.g . C final -1 ° ° t final – 20.0°C = 42.8°C t final = 42.8°C + 20.0°C = 62.8°C 3. q cal = C cal * Δ t C cal = 10.34 kJ.°C -1 Δ t = t final – t initial = 25.08°C – 22.0°C = 3.08°C q cal = 10.34 kJ.°C -1 * 3.08°C = 31.8 kJ
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4. [C metal * (t f – t i )] + [m water * 4.18 J.g -1 .°C -1 * (t f – t i )] = 0 (t f – t i ) for metal = 24.0°C – 50.0°C = - 26.0°C [C metal * (-26.0°C)] + [50.0g * 4.18 J.g -1 .°C -1 * (t f – t i )] = 0 (t f – t i ) for water = 24.0°C – 20.0°C = 4.0°C [C metal * (-26.0°C)] + [50.0g * 4.18 J.g -1 .°C -1 * 4.00°C] = 0 -26.0°C * C metal + 836 = 0 1 - O o metal C J. 32.2 C 26 J 836 C = = 5. q = mass x specific heat x Δ T q = 40.0 g x 1.13 J/g o C x (28.0 o C – 10.4 o C) q = 796 g 6. a. The temperature of the calorimeter increases (from 22.75 o
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This homework help was uploaded on 04/10/2008 for the course CHEM 1036 taught by Professor Amateis during the Spring '08 term at Virginia Tech.

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1036 HW 1 _sol_ - General Chemistry 1036 Homework 1...

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