solution_1_calculus

solution_1_calculus - r r ⋅ × = ⋅ × ⋅ × = ⋅ ×...

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ECE 1259 Solution for Assignment 1 1. a) 2 0 2 2 0 = = + = m m m B A v v b) 1 0 2 1 2 1 0 = = = × m m m a a a C B z y x r r r r r c) 1 , 5 0 5 6 2 1 2 1 1 2 0 2 = = = + + = = × m m m m m m m C B A r r r d) 1 0 2 0 1 2 0 , 0 3 2 2 = = + = = = m m m m m B D A D v r r r 2. ( ) ( ) ( ) [ ] () ( )( [] () ( ) () ( ) () [] 2 C B A C B A C B A A C B C B A C C B A A C B C B A A C C B B A r r r r r r r r r r r r r r r r r r r r r r r r r r r r r
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Unformatted text preview: r r ⋅ × = ⋅ × ⋅ × = ⋅ × ⋅ × = ⋅ × ⋅ − ⋅ × ⋅ × = × × × ⋅ × ) 3. 4. 5....
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This note was uploaded on 04/10/2008 for the course ECE 1259 taught by Professor Chen during the Spring '07 term at Pittsburgh.

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solution_1_calculus - r r ⋅ × = ⋅ × ⋅ × = ⋅ ×...

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