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Unformatted text preview: Physics 212 Classical and Modern Physics Spring 2008 Solutions for HandIn Set #7 A47 Resolution I paced off 184 steps to the point where I could just barely resolve the numerals on the clock, so my dis tance was 184 paces . 75 m 1 pace + 30 ft . 304 m 1 ft = 147 m The diameter of my pupil in bright sunlight is about . 3 cm = 3 10 3 m, so for = 500 nm, my eyes reso lution is = 1 . 22 d = 2 . 10 4 rad . For the angular size of the separation between numbers to be the same as my resolution, then tan (2 . 10 4 rad) = x 147 m , where x is the linear separation between the numerals. So, x = 147 tan (1 . 1 10 4 rad) = 3 10 2 m = 3 cm. A88 In this twoslit problem, were looking for the angle be tween the centeral maximum and the third side maxi mum. third side max central max At the angle of the third side maximum, = 6 , so r = 2 = 3 . But this path length difference is related to the angle by r = d sin where d is the separation between the slits. So, sin = 3 d = 3(633 10 9 ) 3 10 6 = . 633 and = 39 . 3 . A90 We can calculate the path lengths for all three waves directly from the geometry of the problem: 3 m 3 m P 5 m 5 m 4 m The path length difference between the waves from the top and middle speakers is r = 1 m, and we get the same value for the path length difference between waves from the middle and bottom speakers. This gives a phase difference of...
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This homework help was uploaded on 04/11/2008 for the course PHYS 212 taught by Professor Ladd during the Spring '08 term at Bucknell.
 Spring '08
 Ladd
 Physics

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