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Unformatted text preview: Physics 212 Classical and Modern Physics Spring 2008 Solutions for Hand-In Set #7 A47 Resolution I paced off 184 steps to the point where I could just barely resolve the numerals on the clock, so my dis- tance was 184 paces . 75 m 1 pace + 30 ft . 304 m 1 ft = 147 m The diameter of my pupil in bright sunlight is about . 3 cm = 3 10- 3 m, so for = 500 nm, my eyes reso- lution is = 1 . 22 d = 2 . 10- 4 rad . For the angular size of the separation between numbers to be the same as my resolution, then tan (2 . 10- 4 rad) = x 147 m , where x is the linear separation between the numerals. So, x = 147 tan (1 . 1 10- 4 rad) = 3 10- 2 m = 3 cm. A88 In this two-slit problem, were looking for the angle be- tween the centeral maximum and the third side maxi- mum. third side max central max At the angle of the third side maximum, = 6 , so r = 2 = 3 . But this path length difference is related to the angle by r = d sin where d is the separation between the slits. So, sin = 3 d = 3(633 10- 9 ) 3 10- 6 = . 633 and = 39 . 3 . A90 We can calculate the path lengths for all three waves directly from the geometry of the problem: 3 m 3 m P 5 m 5 m 4 m The path length difference between the waves from the top and middle speakers is r = 1 m, and we get the same value for the path length difference between waves from the middle and bottom speakers. This gives a phase difference of...
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This homework help was uploaded on 04/11/2008 for the course PHYS 212 taught by Professor Ladd during the Spring '08 term at Bucknell.
- Spring '08