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handin04 - Physics 212 Classical and Modern Physics Spring...

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Unformatted text preview: Physics 212 Classical and Modern Physics Spring 2008 Solutions for Hand-In Set #4 Wolfson Chapter 26-42b Ampere’s Law tells us H ~ B · d~ r = μ I enc . We choose the Amperian loop to be a circle around the wire, right at the surface. This loop has a radius of 0 . 5 × 10- 3 m. The ~ B-field has a constant magnitude, by symmetry. The RHR also says the ~ B-field points directly along the loop, by symmetry. So I ~ B · d~ r = B (2 πr ) = μ I since all the current I flows through this loop. Solve for B : B = μ I 2 πr = (4 π × 10- 7 )(5) 2 π (0 . 5 × 10- 3 ) = 2 . × 10- 3 T . Wolfson Chapter 26-44 For a solenoid, B sol = μ nI , where n is the number of turns per unit length along the solenoid axis. This gives B sol = (4 π × 10- 7 )(3300)(4 . 1 × 10 3 ) = 17 T. Wolfson Chapter 26-66 P 1 P 2 R We have cylindrical symmetry, and the magnetic field must be circular around the center of the tube....
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handin04 - Physics 212 Classical and Modern Physics Spring...

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