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Unformatted text preview: Physics 212 Classical and Modern Physics Spring 2008 Solutions for HandIn Set #4 Wolfson Chapter 2642b Amperes Law tells us H ~ B d~ r = I enc . We choose the Amperian loop to be a circle around the wire, right at the surface. This loop has a radius of 0 . 5 10 3 m. The ~ Bfield has a constant magnitude, by symmetry. The RHR also says the ~ Bfield points directly along the loop, by symmetry. So I ~ B d~ r = B (2 r ) = I since all the current I flows through this loop. Solve for B : B = I 2 r = (4 10 7 )(5) 2 (0 . 5 10 3 ) = 2 . 10 3 T . Wolfson Chapter 2644 For a solenoid, B sol = nI , where n is the number of turns per unit length along the solenoid axis. This gives B sol = (4 10 7 )(3300)(4 . 1 10 3 ) = 17 T. Wolfson Chapter 2666 P 1 P 2 R We have cylindrical symmetry, and the magnetic field must be circular around the center of the tube....
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This homework help was uploaded on 04/11/2008 for the course PHYS 212 taught by Professor Ladd during the Spring '08 term at Bucknell.
 Spring '08
 Ladd
 Physics

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