Textbook 29

# Textbook 29 - Assignment 7 Solutions Each of the...

This preview shows pages 1–2. Sign up to view the full content.

Assignment 7 Solutions Chpt 29 15. Each of the semi-infinite straight wires contributes R i π μ 4 / 0 emiinfinite B (Eq. 29-7) to the field at the center of the circle (both contributions pointing “out of the page”). The current in the arc contributes a term given by Eq. 29-9 pointing into the page, and this is able to produce zero total field at that location if arc s 2.00 B = , or 00 2.00 ii R R μφ ππ ⎛⎞ = ⎜⎟ 44 ⎝⎠ which yields φ = 2.00 rad. 36. Using Eq. 29-13, the force on, say, wire 1 (the wire at the upper left of the figure) is along the diagonal (pointing towards wire 3 which is at the lower right). Only the forces (or their components) along the diagonal direction contribute. With θ = 45°, we find the force per unit meter on wire 1 to be () 22 11 2 1 3 1 4 1 2 1 3 2 2 3 | | 2 cos 2 cos 45 2 4 T m A 15.0A 3 1.12 N/m. 8.50 10 m FFFF F F aa a μμ =+ += + = ° + = ×⋅ == × × rrr −7 −3 π π π1 0 10 2 0 i The direction of is along 1 F r ˆˆ ˆ (i j)/ 2 r =− . In unit-vector notation, we have 1 (1.12 N/m) ˆ ˆˆˆ (i j) (7.94 N/m)i ( 7.94 N/m)j 2 F × = × + × r -3 -4 10 47. For , ra 2 0en c 0 0 0 0 0 2 3 rr iJ r B r J r rdr J a a = = ∫∫ pp p .

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 4

Textbook 29 - Assignment 7 Solutions Each of the...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online