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Unformatted text preview: 1.0 X 103 4 X 104 7.2 X 107 1.0 X 103 1.0 X 103 6 X 104 1.1 X 106 1.0 X 103 1.0 X 103 8 X 104 1.4 X 106 1.0 X 103 1.0 X 103 1 X 103 1.8 X 106 1.0 X 103 [Fe] = V x M = .002 L X .200 M = 4.0 X 104 [SCN] = V X M = .0002 L X .002M = 4.0 X 107 K = [Fe(SCN)[Fe3+] [SCN] = X 107] / [(3.9 X 104 )(3.5 X 107)] = 5.4 X 103 [SCN] K 1.9 X 104 3.2 3.9 X 104 1.8 6.0 X 104 1.8 8.0 X 104 1.8 1.0 X 104 1.8 [Fe(SCN)2+] = (A  intercept) / slope = .249.0516 / 261465 = 7.5 X 107 [Fe] = V x M = .002 L X .200 M = 4.0 X 104 [SCN] = V X M = .0002 L X .002M = 4.0 X 107 K = [Fe(SCN)2+] / [Fe3+] [SCN] = [7.5 X 107] / [(3.9 X 104 )(3.5 X 107)] = 5.4 X 103...
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This note was uploaded on 04/11/2008 for the course CHEM 2 taught by Professor Ryan during the Spring '08 term at Marquette.
 Spring '08
 RYAN
 Equilibrium

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