P150_Exam2_F07sol - Physics 150 1. 2. 3. 4. 5. 6. 7. 8. 9....

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6. Answer = B 16. Answer = D 7. Answer = C 17. Answer = B 8. Answer = D 18. Answer = E 9. Answer = D 19. Answer = D 10. Answer = C 20. Answer = C Physics 150 Exam #2 Solution 11/5/07 1. Answer = E 11. Answer = E 2. Answer = D 12. Answer = C 3. Answer = A 13. Answer = D 4. Answer = B 14. Answer = E 5. Answer = C 15. Answer = A
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To the right. F average 480 N = F average J t := To the right. J p B := Impulse = change in momentum: p B 9.6kgmsec -1 = p B m B v Bf v Bi () := t 0.02 sec := D and E) Hence this is an elastic collision. K f 392 kgm 2 sec -2 = K f 1 2 m A v Af 2 1 2 m B v Bf 2 + := K i 392 kgm 2 sec -2 = K i 1 2 m A v Ai 2 1 2 m B v Bi 2 + := In elastic collision the kinetic energy is the same before and after: C) To the right. v Af 7.6msec -1 = v Af m A v Ai m B v Bi + m B v Bf m A := m A v Ai m B v Bi + m A v Af m B v Bf + := Conservation of momentum in one dimension: A and B) v Bf 9.6 m sec := v Bi 8 m sec := v Ai 10 m sec := m B 6kg := m A 4kg := Problem #1: Physics 150 Exam #2 Solution 11/5/07
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E top K A U + := K A E bottom U := K A 1.208 10 5
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P150_Exam2_F07sol - Physics 150 1. 2. 3. 4. 5. 6. 7. 8. 9....

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