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P150_ExamF_F06sol

P150_ExamF_F06sol - Physics 150 1 2 3 4 5 6 7 8 9 10 11 12...

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Only the force of static friction exerts a torque on the wheel about the center of mass axis. τ cm r wheel F friction := τ cm 6N m = Newton's second law for rotations, τ = I* α , yields: I cm τ cm α := I cm 1.2kgm 2 = C) At the contact point the only torque is produced by the applied force: τ P r wheel F app := τ P 10N m = I P τ P α := I P 2kgm 2 = D) The top of the wheel is a distance 2*r wheel from the contact point. a top 2r wheel α := a top 4 msec -2 = Physics 150 Final Exam Solution 12/15/06 Problem #1: F app 25 N := m wheel 5kg := r wheel 0.4 m := a cm 2.0 m sec 2 := A) The force of static friction opposes the motion.
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P150_ExamF_F06sol - Physics 150 1 2 3 4 5 6 7 8 9 10 11 12...

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