P150_ExamF_F07sol - Physics 150 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Answer = E Answer = C Answer = C Answer = B Answer = B Answer =

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Answer = D 35. Answer = D 15. Answer = B 34. Answer = D 14. Answer = D 33. Answer = D 13. Answer = C 32. Answer = B 12. Answer = C 31. Answer = A 11. Answer = C 40. Answer = B 20. Answer = D 39. Answer = A 19. Answer = A 38. Answer = C 18. Answer = D 37. Answer = B 17. Answer = B 36. Answer = B 16. 25. Answer = B 5. Answer = E 24. Answer = B 4. Answer = D 23. Answer = C 3. Answer = A 22. Answer = C 2. Answer = E 21. Answer = E 1. Physics 150 Final Exam Solution 12/14/07 Answer = D 30. Answer = E 10. Answer = B 29. Answer = A 9. Answer = A 28. Answer = B 8. Answer = C 27. Answer = D 7. Answer = D 26. Answer = A 6. Answer = D
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y 69.326 m = yy o v o sin θ () t + 1 2 gt 2 := t 3.761sec = t v o sin θ g := At the top v y = 0. B) θ f 5.176 deg = θ f atan v y v x := v f 25.917 msec -1 = v f v x 2 v y 2 + := v x 25.811 msec -1 = v x v o cos θ := v y 2.338 msec -1 = v y v o sin θ := y 69.047 m = o v o sin θ t + 1 2 2 := A) y o 0m := t 4 sec := θ 55 deg := v o 45 m sec := Problem #1: Physics 150 Final Exam Solution 12/14/07
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Kinetic friction on A: F kA µ k F NA := F kA 3.92 N = x-forces: F x FF AB F kA := F F x m A a := F x 1.794N = F AB kA F x := F AB 34.286 N = Newton's Third Law: F BA F AB := F BA 34.286 N = D) For box C: F gC m C g := F gC 39.2 kgmsec -2 = y-Forces: F y F NC F gC := F y 0 := No vertical motion.
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This note was uploaded on 04/10/2008 for the course PHYSICS 150 taught by Professor Naik during the Winter '08 term at University of Michigan.

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P150_ExamF_F07sol - Physics 150 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Answer = E Answer = C Answer = C Answer = B Answer = B Answer =

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