chem 1 lab recitation Stoichiometry

chem 1 lab recitation Stoichiometry - COLLEGE CHEMISTRY I...

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Unformatted text preview: COLLEGE CHEMISTRY I Lab Recitation: Stoichiometry NAME:__________________________________________________________________________ 1. The reaction used to prepare white phosphorous is shown below: 2Ca 3 (PO 4 ) 2(s) + 6SiO 2(s) + 10C (s) P 4(g) + 6CaSiO 3(l) + 10CO (g) . a. How many moles of SiO 2 and how many moles of C are required to react with 1.676 moles of Ca 3 (PO 4 ) 2 ? The molar ratios of SiO 2 to Ca 3 (PO 4 ) 2 and C to Ca 3 (PO 4 ) 2 are 6/2 and 10/2 respectively. Thus: n calphos 1.676mole = n SiO2 n calphos 6 2 = n C n calphos 10 2 = n SiO2 5.028mol = n C 8.38mol = b. How many grams of SiO 2 and C are required to completely consume 200.0 grams of Ca 3 (PO 4 ) 2 ? mm calphos 310.1692 g mol = mm SiO2 60.0843 g mol = mm C 12.011 g mol = mass SiO2 200g 1 mol 310.1692g 6 2 60.0843g 1 mol = mass SiO2 116.229g = mass C 200g 1 mol 310.1692g 10 2 12.011g 1 mol = mass C 38.724g = c. How many grams of P 4 can be produced from the reaction described in b? mm P4 123.896 g mol = mass P4 200g 1 mol 310.1692g 1 2 123.896g 1 mol = mass P4 39.945g = d. How many molecules of CO are produced based on the reaction described in a? molecules CO 1.676mole 10 2 6.022 10 23 mole 1- = molecules CO 5.046 10 24 = 2. Calcium carbide, CaC 2 , used to produce acetylene, C 2 H 2 , is prepared by heating calcium oxide and carbon to high temperature. Carbon monoxide gas is formed as a by-product. a. Write down the balanced equation for this process. CaO (s) + 3C (s) CaC 2(s) + CO (g) b. If a mixture contains 1.15 kg of each reactant, how many grams of calcium carbide can be prepared? We dont know which of the reactants is limiting, so we will calculate the amount of CaC 2 which could be produced starting from 1.15 kg of either reactant understanding that only the lowest value will be the correct one. mm CaO 56.0794 g mole = mm C 12.011 g mole = mm CaC2 64.102 g mole = mass CaC2 1.15kg 1000 g kg 1 mole 56.0794g 1 1 64.102g 1 mole 1 kg 1000g = (starting with CaO) mass CaC2 1.315kg = <--------the correct answer mass CaC2 1.15kg 1000 g kg 1 mole 12.011g 1 3 64.102g 1 mole 1 kg 1000g = (starting with C) mass CaC2 2.046kg = <-------this answer is not physically meaningful 3. A mixture of calcium fluoride and sulfuric acid is heated to drive off hydrogen fluoride.A mixture of calcium fluoride and sulfuric acid is heated to drive off hydrogen fluoride....
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chem 1 lab recitation Stoichiometry - COLLEGE CHEMISTRY I...

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