CHM2045exam2worked solutions

CHM2045exam2worked solutions - Solutions to Exam #2 Form...

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Solutions to Exam #2 Form Code A (Spring 2008) 1. λ = c/ ν = (3x10 8 m/s) / (1.499x10 10 m) = 0.02 m = 2.0 cm (Answer c) 2. E = h ν = (6.626x10 -34 J•s)(1.3x10 15 s -1 ) = 8.6x10 -19 J (Answer a) 3. 1/ λ = R [(1/n 1 2 ) – (1/n 2 2 )] = 1.097x10 7 m -1 [(1/16) – (1/ 36)] = 3.809x10 5 m -1 So, λ = 1 / 3.809x10 5 m -1 = 2.625x10 -6 m = 2625 nm (Answer b) 4. Ionization of the H atom refers to complete removal of the electron (i.e., n 2 = ), so: 1/ λ = R [(1/n 1 2 ) – (1/n 2 2 )] = 1.097x10 7 m -1 [(1/9) – (1/ )] = 1.219x10 6 m -1 So, λ = 1 / 1.219x10 6 m -1 = 8.2x10 -7 m = 820 nm (Answer d) 5. The number of radial/spherical nodes for any orbital can be determined by: n – l – 1, so for a 4p orbital, n=4, l =1, and n – l – 1 = 2 (Answer c) 6. A 3d orbital indicates that n=3, l =2, m l =(-2,-1,0,+1,+2), and m s =(±½), so only (Answer b) (3,2,2,+½) is possible for a 3d orbital. 7. Ionic character of a bond refers to the Δ EN (difference in electronegativities) between bound atoms/ions, so the bonds between a metal and a nonmetal are obviously more ionic in character than those between two nonmetals. K F and Ca O are the most ionic in character, with K F having the greater Δ EN and therefore being more ionic in character. Br Br has a Δ EN = 0, so it is least ionic in character. The Δ EN of C F is greater than the Δ EN of N O, so C F is more ionic in character. Given all this, the only possible answer is: Br Br < N O < C F < Ca O < K F (Answer a) . 8. All of the given species are isoelectronic (same number of electrons in the same configuration), so the determining factor for size is the nuclear charge of each. The greater the nuclear charge, the stronger the pull on the electrons, and the smaller the atom/ion. So, Ca 2+ < K + < Ar < Cl - < S 2-
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This note was uploaded on 04/10/2008 for the course CHM 2045 taught by Professor Mitchell during the Spring '07 term at University of Florida.

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CHM2045exam2worked solutions - Solutions to Exam #2 Form...

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