#Chem 161-2007 Chapter 6 - Thermodynamics practice problems

#Chem 161-2007 Chapter 6 - Thermodynamics practice problems...

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CHEM 161-2007 CHAPTER 6 - THERMOCHEMISTRY PRACTICE PROBLEMS DR. ED TAVSS Heat and work Enthalpy Enthalpy of form’n
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HEAT AND WORK 15 Chem 161-2006 Final Exam Chapter 6 – Thermochemistry Heat and Work What volume change will a system undergo if it absorbs 4.55kJ of heat and ΔU is 3.26kJ and the external pressure is 0.833atm? A. The system will be compressed by 15.3 L B. The system will be compressed 1.55L C. The system will expand by 1.55L D . The system will expand by 15.3 L E. The system will expand by 1.29L ∆E = q + w ∆E = q – P∆V ∆V = (∆E –q)/-P ∆V = (3260J – 4550J)/(-0.833 atm) Convert J into Latm 3260J x (1Latm/101.3J) = 32.18 Latm 4550J x (1Latm/101.3J) = 44.92 Latm ∆V = (32.18 Latm – 44.92 Latm)/(-0.833 atm) = +15.29 L Since ∆ means final minus initial, then +15.29 L means an expansion of 15.29 L. Note: I think that the key, which says “B”, is incorrect. D CHEM 161-2006 EXAM II THERMODYNAMICS HEAT AND WORK 10. A gas absorbs 125 J of heat and expands from 2.00 L to 5.00 L under a constant pressure of 1.00 atm. Calculat U for this process. (a) 122 J (b) 429 J (c) -179 J
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(d) -122 J (e) 347 J ∆E = q – P∆V q = +125J -P∆V = -1.00 atm x (5.00L – 2.00L) = -3.00 Latm Convert to Joules: -3.00 Latm x (101.3 J/Latm) = -304 J ∆E = +125J -304J = -179J 19 Chem 161-2005 Hourly Exam II Chapter 6 – Thermodynamics Heat and work Assume the sign convention of the text, in which w is positive when work is done on the system. In which of the following processes is the sign of “w” negative? X. A gas is compressed under 2.0 atm pressure Y. A substance undergoes combustion in a bomb calorimeter (constant volume). Z. 1 mole of liquid water vaporizes to 1 mole of gaseous water under atm pressure A. X only B. X and Y only C . Z only D. Y only E. X and Z only X. When a gas is compressed this is work done on the system, and the energy of the system increases; w is positive. Y. When a substance undergoes combustion in a bomb calorimeter, there is no change in volume. Since w = -p∆V, and ∆V = 0, then w = 0, which is neither positive nor negative. Z. When 1 mole of liquid water vaporizes to 1 mole of gaseous water under atm pressure, the gas expands from 0 L to 22.4 L. Expansion is positive work on the environment, and resulting increase in energy of the environment, so it is therefore negative work and negative energy on the system.
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37 Chem 161-2005 Final exam CHAPTER 6 - THERMODYNAMICS Heat and work Which reaction should have a E>0 under conditions of constant temperature and pressure? This problem is flawed.
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This note was uploaded on 04/12/2008 for the course CHEM 161 taught by Professor Vacillian during the Fall '08 term at Rutgers.

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#Chem 161-2007 Chapter 6 - Thermodynamics practice problems...

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