exam 1 key A - C l sswns Exam l 1lul'arsion A '09 February...

Info iconThis preview shows pages 1–11. Sign up to view the full content.

View Full Document Right Arrow Icon
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 4
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 6
Background image of page 7

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 8
Background image of page 9

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 10
Background image of page 11
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: C l sswns Exam l 1lul'arsion A '09 February Milo Multiple Choice Section: - 1. Which one of the following substances should exhibit hydrogen bonding in the liquid state”? i o} PH3 H (D H mid;ch D b) H25 '— 9' H has 1% Flu" @cuaon . ; , 5, a) He * ‘_, to 13mm '9“ e] CH4 “t " g? "‘ CH3 2. How much erierg'glr {heat} is required to convert 248 g of water from U “C to 154 0C? Assume that the water begins as a liquid, that the specific heat of water is 4.184 Jig. “C over the entire liquid range, that the specific heat of steam is 1.99 Jig. “C, and the heat of vaporization of water is 40.?9 kamol (mm was amfiiymsaawgclmt) a. 130 M a. 103+? h: 692 m . iwt H113 “it-4" "I: 6L1 LIE c. 562 kJ @ haw he) m fiso ma ifitlha a. 639 k] - 7'?) i T2) e. 589 k] (933 um aim. {En-z Queer.) 13.1.0163 11300514 sierra 1L3 Arafat-:- mat“: 3. Wthh of the responses includes all of the following substances "I that can form hydrogen bonds? Substances: [1] CH3CDCH3: i2) CH30H; {3) CQHE; {4] HCDOH 4 ab 2 and 4 L L L a. 1 and 3 c3 ‘4 b c.- 1 and 2 C R g,— CHL-H p, a. 1,2 an'd4 / Cu; 1 ~. HFCeoH e. 1,2 and a “a”: (I 13 owoo Exam I 1it"ersion A ()9 Feloruarg,r eooo . s. -x @:€t=ffly fQICEOx '15 4. At room temperature, Sic}: is a solid, whereas CD; is a gas. This is because a. CC]: is molecular, whereasSiQ—Hs—ieaic. €101.35: merit iii-mile C310; Nos. @CD; is molecular, whereas SiCig is a covalent‘hetworh solid f «Jo-f“ one o, “M mWC. Betheromeleeular, but the dispersion forces between Sit): >¢ molecules are stronger because Si02 is the larger of the two compounds go o. both are molecular, but CD; is lineaerEFe-asfi'ififis-hent, - ,1? UN”) and therefore has dipole—dipole attractions. W at [W 5. Which of the following would be expeoTed to have the highest vapor pressure at room Temperature? 2: 03V” {9 1: T V‘ ' a) ethanol, lop = ?3°C 10? P _ A? b} methanol, bp = 65°C 3 - i hold ‘W‘JM outfit”? 5" c]wal'er, hp = 100°C {yo W} I” {T I ce’rone, lop : 56°C “I? Q E. The freezing point of a solution prepared by dissolving no 9 of KCI in 150 g of water is —4.?El “C. Calculate the ean‘t Hoff factor, i, for this solution. K. for water = 1.86 °C!m. m:- Flu-1'3 LC 4 K51“ a. 2.52 _ M r in. Les soofnflbifimb Lee K 1, 3,151.3 no LU'E‘ID "C ' l f h b Aw, ':- EL! m; " E. “GHEG t E ~ f‘ 5 a {we the t oo “3* Wave—mo MAJ” ‘ 1.2“ 3*“. Calculate the molar concentration of a sulfuric acid solution containing 23.0% by mass of stoqrssos gfmol}. The solution densityr is 1.398 gfcm-l. WW l mafia limb ‘fz... 3w. Show“ Jeni-'- - a. {1.328 M b. 5.95 M c. 0.596 M d. 3.28 M . none of the above EU set: E lfLmiflE‘fl/l?‘ to. J In digit)qu KLE- i. 233: loofl W“ C1 sawoo Exam 1 Version A [39 February soos 3. What change would you predict in the solubility of Nfig} in water if the temperature changes from 2D uC to 80 W22? 131.99 less will dissolve w “firm #-—- . more will dissolye F Wm @ c. the solubility will not change high “T d. not enough information 9. Use the graph of yopor pressure to determine the normal boiling point Of CHCIg, k) K W C}... car %0 W “‘5 Vapor Pressure mmHg D 10 20 30 4B 51‘.) 6t] TO BE! Ell} 1Gfl11012fl T”; o} 19°C b) 52°C ClfioWflfi Exam 1 ~II:i'el'sion A 139 February,r 23136 ' Ionic. a} g 10. Arronge The following in order of increasing boiling poin’r‘. RbCI, CHsfl'i, ~ t" , '4? CHaflH.CH-i. inn EMF}; dif'dtPle saw fl dis? mafia! L? dz.st- o} CH30H < CH3C| < RbCI < CH4 .3 b) CH4 ‘1 CHsflH < CH3Cl < RbCl c) RbCI < CH3Cl < CHaflH < CH4 @CH4 < CH3Cl 4 CHaflH < RbCl e) CHg'DH < CH4 < CH3CI < RbCl 11. Which of The following characteristics indico'res The presence of weak inTerrnoleculor forces in o liquid? «1; ms i=3, Wis 'a- --a IRE.- g o low heel of 1iropor'izo'i'ion “:15. Wt; MW 0%%S er—o—Iowwpor-pressure- _ chng-Jzo ' ' ds—ewhigh-erisieel—semperosure Al“ LEM}? e. None of The above. 12. According To Rooui'r's low, which s’roiemeni is foise? LP? P115 >R‘ililfil Mm _ o) The vopor pressure of o solven‘r over o solo-lion decreases os i'rs mole frocTion increases. (as soth is Lids-u in mews Np mm ' thesoiubfiifi-ofe—gosincwesesshe—sempereWMeoneosesrc ®rhe vapor pressure of o soivenf over o solution is less than ThoT o pure solvent amwmssnmmmmwssl CWWW .HM ow;- 1 crossed was W ima- nlfi‘hW-th‘b on M W“? ism so {Lo-Ends? .-— Jo- CIJEWflfi Exam i ‘v’ersien A _ W use 09 February 26% 55M 'H'Wfl‘ )1 a)“ '3' W 13. The Sfitubiii‘f'f of niTrugen'gas eT 25°C and a nitrogen pressure of 522 mmHg is 4.? x 10' 4 melfL. WheT is The value of The Henry's Lew ? censTanT in melfL-eTm? f 3.: he, ? : “Blew e .E x 10'4 meifL-aTm 1.1I pp; 61% my 3 K H i m mar/'5“ b} 4.7 x HT“ melfL-eTm 1. D-LoEflr crew e] 3.2 x 1i?!"4 melfLeTm H514 Lf—m‘h'" d) 9.0 x 10"? melfL-eTm K“ I {p '8‘ % LEL e}1_5 x 103 mnlfLreTm Limp" fl and; 14. WheT is The molar mass of Toluene if 0.35 g of @Wsses The \ freezing peinT of 1013.51 of ben2ene by DATE? K1: of benzene is L” 5.12°Cfm. e * {37$ =O.LT:{—Cr= eke-W's @935 gfmsl .3, i Lesrfi im 1m) b} ?8.0 grime-I c310,? gxmor 1m: gm 2: mi Ami £131-- L (1081.8 gfmei 1i 5 m. e} 92? gfmel L = sfie sex “:73 mi 4mm emsszm 15. For The reaeTien Bros" + 53r‘+ EH‘ —e SBrz + SHED eT a perTieular “1.2x. ifilwi Time, —e[Br03']x’eT = 1.5 x 10'? Ma’s. WhuT is -e[Br']feT aT The same w £125 (:1 insTenT? {,1 ii ewifhm M 1.451: “f 1 1%.!‘03fl )W e)13 We .. _ . .5x10'2M1’S W”- “e‘ E“ E” '5“ ‘H (31.5 x ie-ans We. as Wen—mm d)3.flxlfl' This 9. :5}; figs.” 4%,,“ weer:ng e) 330 Ma’s fl“ eh“ C130W00 Exam 1 Versi0n A 139 Fclal'uer}r 213% 10. NiTric axide gas {ND} reacTs wiTh chl0rine gas according T0 The 1r equaTian 45% ND+%CI2—*NDCI. ("mil-QaKCND—JFEC121T [3 E The f0|i0wing iniTiai raTes 0f reacTicn have been measured TM The '3 given reagenT c0ncenTraTi0ns. {3m I % 2_ 1"?" . 3 e 9 it EXET. # Rafe ithr} MD M 12sz {gawimc HE? A: m 1 1.19 0.50 0.53 CNN reek—i 9541 * 1%: 4.?9 1.00 0.50 ,.-, 2 re 000” s “g 3 9.59 1.00 1.00 i 3, 1 e0 t; in )J i“ Which of The failawing is The raTe law {raTe equaTian} far This 90m 2 g_ 3 8 S reccTian? "h" a) raTe = HMO] scam Wit-i b]nfie=flNGflflfl”2 fiTgmhfl c) raTe = k[NC-'][Cl2] \j = ‘1 = 2 | . . @ra‘i'e k{N01 [c 2] {MW K EMU]: [1113 e) raTe = ktm0ficlzf 1?. Far whaT 0rder reacTian daes The half-life geT langer as The iniTifll cancenTraTic-n increases? . .etel “big 1 {nuclei 43—- A-‘J 0"” $33? It‘lii .2 eraTh 0rder "2.1L _ I a m mic-fled an c.9111: till: reg-r c} secand arder Jul: Chm; _ ,Wzr 2,: flag ‘ ‘ _ d} n0ne 0f Them because ha|f+life Israiwaymdependenfuffihenmrul- c0ncenTraTi0n 1b? 11kg mpd M kfléflfl CW . M‘EM C13 611.306 Exam 1 Version A 09 February 2000 18. A second order reaction has a rate constant of 1.0 x 10'3 i ‘1 Lrnol'15'1. It the initial reactant concentration is 0.200 mow—emits long will it take for the concentration to become 0.0250 M?__., {at 3.5 x 10“ s 1. 3 4r . 8000 s "* s “7‘ c. 4.0x10" 5 [Pat Um? _ /’ d. 35me i # _1_ i Q_Wm?)tt) e. sexing? alga-53’" am hi ' — H - s Um * 't- EEDEDE - 3.53m 19. The number of atoms in a face-centered cubic unit cell is Lt- L/w-D‘L E: a)1 Jimficmm—FAoo'eS b]2 ‘ £33 warmest,“ th e}8 20.The reaction [42(9) + I49} —) 2 HI(g) is exothermic and has the foliowing rate low at 393K: rate = [H2][Iz]. Addition of a catalyst would a. increase the rate of the forward reaction is. increase the rate of the reverSe reaction (a increase the rate of both the forward and reverse reactions d.causeaa.iaccea Eur 5r LDWS 1‘1“ (tan an M? as CL iamva‘ a; W flu“ lime 1W? {\KF‘ES {.31 sowoo Exam ] Version A (19 February Zfl'flfi nol‘ EWIHT 21. For Theemical reocTion shown below. which one of The following sToTemenTs con be rigidly assumed? ZHQ‘Sig) + 03(9) —:- 25(s) + EHEDU) . ‘35 ‘fi’T‘ I will” EM 3 . A. The reoeTion is Thirdeorder overcll. '9“ fiw B. The reocTion is second-order overall. 393W mwflk) c. The roTe low is. roTe = knee]? [02]. snow ' The roTe low is. roTe = k[H25] [02]. he reTe low connoT be deTermined from The informaTion given. 22.Which of The following is nor True wiTh regard To oner? o] WoTer has on high head copociTy. of lo} WoTer has on unusuollg.»r high boiling poinT. v” c] WoTer' 1con": form hydrogen bonds. M” @Ice secs-'5: dense Than liquid oner. e) WaTer‘ is a polor molecule. yr- 23.When The concenTroTions of reocTonT molecules are increased, The raTe of reaeTion increases. The besT explanoTion for This phenomenon is__ThaT as The reocTonT concenTroTion increases. . . . ~ 'Tb WWWth M define EM WT: The freouenc}T of molecular collisions increases. Wie-Mkj ET New "TE—- ci—sr’hll. same {We 3-111 3H m H C I sewos Exam 1 Version A {19 February EDDIE 24.Which one of the following changes would alter the rate constant (k) for the reaction 2A + 3 —~ products? - mess-oil marsh ®increasing the temperature D. Wing—Wmmamniona—while 25..For the chemical reaction A —+ C, a plot of versus time was found to give a straight line with a positive s pe. What is the order of reaction? a] zeroth d) Such a plot cannot reveal the order of the reaction. 2a.Which one of the following substances crystallizes as a covalent crystal? _a-}.—CwaGH-— ia an L sjcog ._s WWW“ c] as a weave a KMhm Jame-L SlU2 H 5? PH: Al" 2?. Using the following phase aiagremr what happens when pressure is aopiiea to the substance at point A. C136w06 Exam I Version A D9 Febms = 20136 Pressure {aim} Ii! —k fie 7:- 5'3 m 1913 2131] 311! dill-l] EDD EEHJ TE'T‘ Dersture [‘10) a. freezes mess #3,» Wm Sr—e- Cl. C. vaperizes d. condenses e. subiimes 23.6ulculu’re “the melaii’ry of e selufion can‘taining 14.3 g of Mail! in 112.2 g of water. “345*10‘jm Me a use) my mm a 5&0 m b] 5.30 x10" m ..__ fl I “L1 c) 2.45 x 10-1 m c} es; 2 13 was \5ea'e’fl 5H d).103 m see m Cl sowos Exam 1 Version A '09 February zoos Free form answer (10 points) Border oops in Defroi'r stop o cor coming over from Windsor. In The cor, she}.r find a smell bog of white powder. Cops suspect The powder is herein [CzinsNDi 359.42 gfmol). A small sample is seni' “to o forensics lob for analysis. A soien’risT in The lob dissolves 0.0100 g of The substance in 2.00 g of benzene. The Solution freezes of 533° , Con “the scientist conclude ihe subssonee is heroin or noi? Explain. {A YES or No answer will receive no eredi’r even if if is oorreo’r. You must jusfify your answer with o mothemo'rieol solution.) The normal freezing poini' of benzene is 550°C and Kf for benzene is 5.12°Um) Marimba-J. wwszsio Dix—u MA, +1». MW Clix (answer-e Ewi” law-r1 MAW "H: \I, v)! WW Cu'l‘r mln‘ ‘i‘iitj ... m1 Ju— bbfifilfi'gmbfi ...
View Full Document

Page1 / 11

exam 1 key A - C l sswns Exam l 1lul'arsion A '09 February...

This preview shows document pages 1 - 11. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online