Stoichiometry+Part+2

# Stoichiometry+Part+2 - 4. Add solvent (DI water) until the...

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Stoichiometry Part 2 Solution Stoichiometry Fundamentals Key terms – Solute, Solvent, Concentration (amt of solute / given amt soln) Molarity ( M ) = mol solute / L soln Preparing and Diluting Molar Solutions Prepare 0.500 L of 0.350 M nickel(II) nitrate hexahydrate Ni(NO 3 ) 2 6H 2 O (Ni Hydrate) 1. Weigh the solid needed. Mass (g) of solute = 0.500 L soln (0.350 mol Ni hydrate / 1 L soln) (290.82 g Ni hydrate / 1 mol) = 50.9 g Ni Hydrate 2. Carefully transfer the solid to a 500 mL volumetric flask that contains about half the volume of solvent (DI Water). 3. Dissolve the solid thoroughly by swirling.
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Unformatted text preview: 4. Add solvent (DI water) until the solution reaches its final volume, 500 mL. M dil V dil = M conc V conc If 25.0 mL of 7.50 M sulfuric acid are diluted to exactly 500. mL, what is the mass of sulfuric acid per milliliter? Solve Despite their toxicity, many compounds of lead are used for pigments. a) What volume of 1.50 M lead(II) acetate contains 0.400 mol of Pb 2+ ions? b) When this volume reacts with 125 mL of 3.40 M sodium chloride, how many grams of solid (ppt) lead(II) chloride can form? Solve 1...
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## This note was uploaded on 04/13/2008 for the course CHM 2045 taught by Professor Mitchell during the Fall '07 term at University of Florida.

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