Yellow Test Answers

Yellow Test Answers - Answers (YELLOW test}I m da 1hr 1min...

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Unformatted text preview: Answers (YELLOW test}I m da 1hr 1min — m 1105 points} a = 4 me’is dag) = —— = 5x10 5— = 4.7x10‘6 "g" s dag 24 hr so min so 3 s?- V 2] (10 pts} distance traveled = (ave speedfltime) or AX =‘Lgu—D-t or 0.05 Wt 3] {15 pts) a)LetT"1 represent one of the beams and-r'z the other fi' bg the Pythagorean theorem: [HI = [le = 5!? m “—_— 7.2 71 T": o'r‘z = (53:15» (5)(-5)+(5}(5) = 25 m2 also: 7’1 or} = [F1 I fizlcosqa = [5f312cosqj = 1'5 costp rn2 -. coscp = 25275 = 13 or tp = cos"(1f3}= 70.50 b) (10 pts} Just make this a vector problem, as I did in class with mg "hike around a circular path." Let fibe the edge of the brace. From the diagram above: 7'2 =_r°1 + E or fi' =‘r’2 —'r'1 = (5,-5,5) - (5,5,5) = (0,—10,o) or R = Ifi'l = 10 m 4] (10 pts} This is essentiallg the extra credit problem (which I also did in class). At time =T the bug is at location :4 = U’zaT2 and moving at speed v = aT Now the bug decelerates and its speed drops to 0: V v2 — v02 = 2a(x - x0) or 0 - (aTZl2 = 2(-a}(x - 1X2aT2} solve to get x = aT2 5] (20 pts} starting conditions: for No—No: x0 = 0 v0 = 10 ftfs a= 0 for Liberal: x0 = 30 ft 'v'g = 0 a = 2 ftx’s2 equation of motion f or No—No: x = 10t equation of motion for Liberal: >4 = 30 + t2 when they meet: XN = xL or 10t = 30 + t2 solve to get: t = [10 1 J-20 11'2 = imaginarg => theg never meet, the Liberal is spared! 6] {15 pts each} a)g = gg+vogt+1f2agt2 or 0 x= xo+voxt+1f2axt2 or' x 500 + 0 —1:"2gt2 solve to get t = 10 sec 0 +(15'130'1t1I + 0 = 1500 m b) vx = constant = 150 ms’s and v9 = v09 - gt = 0 -(9.EI}(10} = -98 mJ’s therefore? 150? -98’j‘ mfs when bomb hits the ground Name- A SHOW YOUR WORK IF YOU WANT CREDIT Here are some conversion factors: 1 inch = 2.540 cm; 12 inch = 1 foot; 1 mile = 5280 ft,- 100 cm = 1 meter; 1 slug = 14.59 kilograms; 211' radians = 360° = 1 rev; "9" = 9.8 mills2 = 32 fte's2 V1] The Japanese satellite Hagabusa is now in solar orbit and will rendezvous with an asteroid named Itokawa. The satellite‘s ion engines can accelerate it at a = 4 meters per second per dag. How does this compare to the acceleration "9" that you are used to? ' .. s l 9 “£2723, > __ A? 4’ /D m l—n/s '1 @— /y%‘40? ‘5 , 4 WWWMMWW 5 2/ £00 ' a @ 5 C73 ._ 21(éé3 MM” M a \ >‘\UJ‘ c4» 5 3 r I D’ 1/ < \ ¥ ‘ ‘ W'”"‘"“ W““J”Mm§4w:mwrmnN\»‘.‘.AAIWMINN\WWMflw>mmmmmwhuwm.mmum,*q in” UN ‘Ye.,,,_,.N,w.,v.u.w,wu. ., mutiny”. w— vvvww'v.w¢m:mw.»~~me-—m~:mwfls;.a\ a r as a w W A m w we mo a w l 0 ‘ \ 5W 1 W 4'94“ 65"“ 47C 9 f“ WW"— n M "why v, “mam”, . .ww.._m_‘___m_ 2] A bullet is fired completelg through a board that is 5 cm thick. The bullet enters at speed 200 mfs and emerges at 100 mfs. How long is the bullet in the board? D . . . . . . . . . . . . .. V 0. O§ I 0 + 200(S';>+ gl‘a(g. :: I00 0 05 61"” 2 is» Q __ A DVD + J” 0i , fiDDA ,g 0 " fl + gflz 7» < 800* ’3 0.03 A Maw villa 1' 80’ a 2‘ ZUUZSm/sz /’Q/ ’ JDGAAFW ’3 rallying at? 5] Republican Captain hip—No spots a libeggding 30 feet away who is trying to register voters. Captain No-No wants to stop this and runs toward the liberal at a constant 10 ftfsec. The liberal sees the danger and flees on his solar—powered scooter which has an Vacceleration of only 2 ftISZ. What happens? m Now» lye/2 2!” 5‘ A”; I 415 30474- X2 3 X02 «- V2+ (@ (“‘4‘ “AA” : o + ID4- Xk: /O‘f 0‘ ‘ Email. We 9"‘3 b‘ ° etc/«whorl; o Mo4fl‘fl ‘4'" \_/ 56L Q @14sz POSIJ-IOA a“?! /— m) H- wou’d 4"?“ 6’7“ ...
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This homework help was uploaded on 02/08/2008 for the course PHYS 141 taught by Professor Staff during the Spring '06 term at Cal Poly.

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Yellow Test Answers - Answers (YELLOW test}I m da 1hr 1min...

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