ME320 solution7 - ME320 Thermodynamics Homework set #7 Due:...

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Unformatted text preview: ME320 Thermodynamics Homework set #7 Due: Wednesday 11/05/03 at the start of class 1. For a cycle, is the net work necessarily zero? For what kind of systems will this be the case? Solution: No. This is the case for adiabatic systems only. 2. Can a steady-flow system involve boundary work? Solution: No, theres no boundary work for a steady-flow process. 3. 4-79 (Textbook) p 1 = Steam mass flow rate = 12 kg/s 10 MPa T 1 = 450 C p 2 = 10 kPa x 2 = 0.92 V 2 = 50 m/s o V 1 = 80 m/s Solution: This is a steady-flow process since there is no change with time. Po- tential energy changes are negligible. The device is adiabatic and thus heat transfer is negligible too. From the steam tables (Table A4 through A6) For P 1 = 10 MPa and T 1 = 450 C, 1 = 0 . 02975 m 3 /kg and h 1 = 3240 . 9 kJ/kg and For P 2 = 10 kPa and x 2 = 0 . 92, h 2 = h f + x 2 h fg = 191 . 83 + 0 . 92 2392 . 8 = 2393 . 2 kJ/kg (a) The change in kinetic energy is determined from ke = V 2 2- V 2 1 2 = (50 2- 80 2...
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ME320 solution7 - ME320 Thermodynamics Homework set #7 Due:...

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