MiniHSC1Solutions - MiniHSC 1 i 4 VI§2=242 41I2=642...

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Unformatted text preview: ' MiniHSC 1 i) 4§+VI§2=242+41I2=642 ii) (343?: 9x3 = 27 V13 2 ->sinB-'2— HIE I 3 . 2_x_ _ a- 1) 3 — 14 —> 3(3)—3(14) => 2x : 42 => x=21 2 ii) x-5x-6=0=> (x-6)(x+1)=0 =>x=-1,6 iii) lxl =6 => X=:t6 . 1:1. 2 _ 1) dx(4x-x)—4-2x .. _d_ _1v2_1-1/2__1_ 11) (“(15K) — dx(x )- 2x — 2‘]; iii) i(6+5x)=2(6+5x).5 =10(6+5x) dx 2 i) y=6x-x $26-2x =6-10,atx=5 x ii) y-5 =-4(x-5) iii) Wheny=0: 0-52-4(x-5) => x = 6% cuts x-axis at A(6i‘ ,0) Whenx=0: y-5=-4(0-5) => y = 25 cuts y-axis at B(0,25) 2 iv) Area AOAB = %(6%)(25) = 78% u Angle AGE 2 112°, BCD is a straight angle (= 180°) Angle ABC = angle BAC = x°, base angles isosceles AABC x + x + 112 = 180, angle sum AABC x = 34° Let my height a year ago be x cm Then 1.02(x) = 147.9 x = 145cm _ .‘I 2 2 1) AB: (2-12) +(3-5) = 4100+4 = «I104 = 24:26 ii) M = (average of x's, average of y's) 2 + 12 3 + 5 = 2 9 2 ) : (7’4) iii) m=m=fi=§ i) a=3andd=9-3=6 ii) Tn: a+(n-l)d T10: 3+(10-1)6 = 57 iii) Sn: §[2a+(n-1)d] s10: '122[6+(10-1)6] = 300 10 11 12 ii) ax ii iii) 2 2 +bx = 3x(x+2)=>ax +bx = 3x +6x a = 3, b = 6 by equating co-eflicients. False ii) False True iv) False ...
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