# Titration Calculations.docx - EXPERIMENT...

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EXPERIMENT: Volumetric/Vinegar Analysis Complete the following tables. Table 1. Standardization of NaOH via Titration. Titration Mass of KHC 8 H 4 O 4 (g) Moles of KHC 8 H 4 O 4 (mol) Volume of NaOH titrated (mL) [NaOH] (mol/L) 1 0.4408 0.002158 10.20 mL 0.2115 mol/L 2 0.4453 0.002180 10.35 mL 0.2137 mol/L Average [NaOH]: 0.2126 M Standard Deviation: 0.001556 %RSD: 0.73% Table 2. Titration of Acetic Acid with Standardized NaOH. Titration Concentration of NaOH (M) Volume of NaOH titrated (mL) Moles of NaOH titrated (mol) Mass of CH 3 COOH in Sample (g) 1 2.0% 16.85 mL 0.003582 0.2167 2 16.00 mL 0.003402 0.2058 Table 3. Determination of Mass Percent Acetic Acid in Vinegar. Titration Mass of CH 3 COOH (g) Mass of Vinegar (g) Mass % of CH 3 COOH Average Mass % 1 0.2167 10.259 2.11% 2.07% 2 0.2958 10.1255 2.03% Standard Deviation: 0.05757 % RSD: 2.73% % Error: 3.5% 1. Calculations (Use equation function in Word to show your calculations. One example for each type of calculation is sufficient.) Grams to Moles : gof Substance× 1 mol KHC 8 H 4 O 4 molar massof substance = mol 1
Sample Calculation: 0.4408 g KHC 8 × 1 mol KHC 8 H 4 O 4 204.23 g mol = 0.002158 mol Molar Concentration: Ml ¿ L : mL× 10 3 L 1 mL = L moles of substance volumeof substance = molar concentration Sample Calculation: