# Lab#2 - Determining the Value of Avogadro's Number...

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Determining the Value of Avogadro’s Number Experiment 2 September 14, 2007

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Calculations Trial 1 Drops of stearic acid used 75 - mL of stearic acid used = drops of stearic used = 75 Average drops per mL 77 = 0.97 mL - grams of stearic acid used = (mL of stearic acid used) x (concentration of stearic acid) = (0.97 mL) x (0.000150 g/mL) = 1.50 x 10^-4 g - moles of stearic acid used = grams of stearic acid used = 1.5 x 10^-4 g = molecular mass of stearic acid 284.47 g/mol = 5.3 x 10^-7 mol - cm^3 of stearic acid used = mL of stearic acid used = grams of stearic acid used Concentration of stearic acid = 0.00015 g = 1 cm^3 calculated 0.00015 g = 0.97 cm^3 - thickness of monolayer = volume of stearic acid = .97 cm^3 Area of watch glass 61 cm^2 = 0.016 cm NUMBER OF MOLECULES Length of stearic acid = 18.4 x 10^-18 cm Diameter of stearic acid = 7.8 x 10^-8 cm Area of stearic acid = (length of S.A.) x (diameter of S.A.) = 1.4 x 10^-15 cm (Diameter of stearic acid)^2 = (diameter of stearic acid)^2 = 6.1 x 10^-15 cm Triangle = (D^2)(square root of 3)/4 = 2.8 x 10^-15 cm A. Laying flat on surface
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