hw5 - thinking in number of standard deviations. Then find...

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a) f(x) = { 1/(310.6-284.7) = 1/25.9 = .03861 for (284.7<=x<=310.6) {0 elsewhere b)P(x<290)= Width= 290-284.7= 5.3 Uniform Height= .03861 P(x<290)== 5.3*.03861= 0.204633 c) P(x>=300)= Width= 310.6-300= 10.6 Uniform Height= .03861 P(x>=300)= 10.6*.03861= 0.409266 d) P(290<=x<=305)= Width= 305-290=15 Uniform Height= .03861 P(290<=x<=305)= 15*.03861= 0.57915 e) P(x>=290)= Width= 310.6-290=20.6 Uniform Height= .03861 P(x>=290)= 20.6*.03861= 0.795366

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Problem 11 Parts Relevant z score Prob a) -1 0.16 b) -1 0.84 c) -1.5 0.93 d) -2.5 0.99 e) (-3<=z<=0) 0.5 Problem 14 Relevant Prob Corresponding z score a) 0.98 1.96 b) 0.48 1.06 c) 0.73 0.61 d) 0.13 1.12 e) 0.67 0.44 f) 0.33 0.44 Instructions Show your Excel work on the left. column c. Then look up Table 1 on page 649 to do both.
. Must use Excel formulas in 9 for comparison. Must learn how

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Let X be the spending on child's back-to-school clothes E(x) 527 Stdev(x) 160 (NORMSDIST) (NORMDIST) x z Prob using z score Prob using x a) \$700 1.08 0.14 0.14 b) \$100 -2.67 0 0 c) \$450 -0.48 0.32 0.32 \$700 1.08 0.86 0.86 0.55 0.55 d) \$300 -1.42 0.08 0.08
Instructions: Determine the associated z score first and make sure that you are

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Unformatted text preview: thinking in number of standard deviations. Then find the probability using two ways, the standard normal (NORMSDIST) and the NORMDIST() function. a. P(x>100)= .8602 b. P(x<100)= .0038 c. P(450<x<700)=.54504 d. P(x<=300)= .07799 E(x) 3.5 Stdev(x) 0.8 (NORMSDIST) (NORMDIST) x z Prob using z score Prob using x Percentage a 5 1.88 0.03 0.03 3.04% b 3-0.63 0.27 0.27 26.60% c 4.53 a. P(z>5)= 3.04% b. P(z<3)= 26.60% c. Upper 10%; how much rainfall (x)? 4.5 inches 130.81 Answer Textbox (show Excel work on the left) Avg=u= 100; Std. Deviation= o= 15; to be in upper 2% Answer: 130.8062 a 0.13 b 0.09 c 0.01 d 81784.44 To the left in excel, or without. .. a. =75000-67000/7000=1.1428571 P(1.1428571)= .8729 1- .8729= .1271= 12.71% b. =75000-65500/7000=1.357141 P(1.35714)= .9115 1- .9115= .0885= 8.85% c. =50000-67000/7000= -2.42857 P(-2.42857)= .0075= .75% d. She would have to make above \$81,784.44 per y would be barely above 99% of her male coworkers. year. So, 81,785 s....
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This note was uploaded on 04/08/2008 for the course COBA 3131 taught by Professor Zang during the Spring '08 term at Georgia Southern University .

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hw5 - thinking in number of standard deviations. Then find...

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