Solution HW Ch 3

# Solution HW Ch 3 - ME 113: THERMODYNAMICS Spring 2008 Ch 3...

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ME 113: THERMODYNAMICS Spring 2008 Ch 3 HW Solution 1

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Problem # 3-15C No. Because in the thermodynamic analysis we deal with the changes in properties; and the changes are independent of the selected reference state. Problem # 3-29 Complete the following table for Refrigerant-134a : T, ° C P, kPa u , kJ / kg Phase description 20 572.07 95 Saturated mixture -12 185.37 35.78 Saturated liquid 86.24 400 300 Superheated vapor 8 600 62.26 Compressed liquid Problem # 3-36 A piston-cylinder device that is filled with R-134a is heated. The final volume is to be determined. Analysis This is a constant pressure process. The initial specific volume is /kg m 1595 . 0 kg 10 m 595 . 1 3 3 1 = = = m V v The initial state is determined to be a mixture, and thus the pressure is the saturation pressure at the given temperature 12) - A (Table kPa 100 C 26.4 - @ sat 1 = = ° P P The final state is superheated vapor and the specific volume is 13) - A (Table /kg m 30138 . 0 C
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## This homework help was uploaded on 04/12/2008 for the course ME 113 taught by Professor Usaxena during the Spring '07 term at San Jose State University .

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Solution HW Ch 3 - ME 113: THERMODYNAMICS Spring 2008 Ch 3...

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