Thermo2 HW #7 Problem#6

Thermo2 HW #7 Problem#6 - 771.27[= J/mol x_EA_partc 0.75...

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HW #7 Problem 6 b) x_B_partb 0.5 delta_H_mix_partb 354.5 [=] J/mol (d(delta_H_mix)/dx_B)_partb 241.2 [=] J/mol H_overbar_B-Vunderbar_B 475.1 [=] J/mol x_EA_partb 0.5 delta_H_mix_partb 354.5 [=] J/mol (d(delta_H_mix)/dx_B)_partb 241.2 [=] J/mol H_overbar_EA-Vunderbar_EA 475.1 [=] J/mol c) x_B_partc 0.25 delta_H_mix_partc 225.04 [=] J/mol (d(delta_H_mix)/dx_B)_partc 728.31 [=] J/mol H_overbar_B-Vunderbar_B
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Unformatted text preview: 771.27 [=] J/mol x_EA_partc 0.75 delta_H_mix_partc 225.04 [=] J/mol (d(delta_H_mix)/dx_B)_partc 728.31 [=] J/mol H_overbar_EA-Vunderbar_EA 407.12 [=] J/mol The amount of heat that must be removed is equal to "delta_H_mix_partc" which is equal to 225 J, because there is only one mole in the system to achieve an isothermal system....
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This note was uploaded on 04/09/2008 for the course ECH 4123 taught by Professor Zeigler during the Summer '07 term at University of Florida.

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