Statistics Final Study Sheet

# Statistics Final Study Sheet - Empirical Rule: 68% of the...

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Empirical Rule : 68% of the time all observations will fall b/t + 1 SD 95% = + 2 SD 99.7% = + 3 SD Ex. Given Histogram: 95% of obs. Fall b/t 12.4 and 46.8 What is the SD? 46.8 – 12.4 = 8.6 x_bar, SD 4 99.7% x_bar – x_hat 6 Normal Probablility: Let x = N(25, 10) What is the probability: P(x>22)? 2 nd DIST | normcdf (22, 9999, 25, 10) (LB, UB, x_bar, Sx) Ex. P(24<x<39) 2 nd DIST | normalcdf (24,39, 25, 10) Ex. P(x<18) 2 nd DIST | normalcdf (-9999, 18, 25, 10) only use binomial pdf if there is “exact” or ”equals” CARS w/o additive w/ additive L3 1 22 26 -4 2 15 19 -4 3 18 17 1 4 28 34 -6 5 12 17 -5 6 25 25 0 7 18 22 -4 L3 = L1 – L2 Want a 95% CI for paired data STAT | TESTS| T-INTERVAL Stats Data Data List: L3 FREQ: 1 95% CI CALCULATE = (-3.14, .05) SD is always positive ME = (CV)(SE) DF = n – 1 DF(independent data sets) = n 1 + n 2 – 2 SE = SD √n

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Proportions: p_hat = # of successes Ex) 100 = .5 Sample size 200 95% CI for a proportion 1-Prop z interval X = 100 CV 90% = 1.645
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## This note was uploaded on 04/14/2008 for the course STAT 2160 taught by Professor Heun during the Fall '08 term at Western Michigan.

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Statistics Final Study Sheet - Empirical Rule: 68% of the...

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