physics 133 Exam2 spring04 - A Name 1 ‘ ‘ Saunders ‘...

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Unformatted text preview: A . _ Name 1; ‘ ‘ Saunders ‘ Physics 133 -- Exam #2 I I ' You must do and show/explain your own work. Partial credit will be awarded. However, a correct answer without explanatory material will not receive full credit. ° Clearly indicate your final result with a box or circle. - If you need more space go onto the back and indicate "OVER". 1 20 --— Possibly helpful information: NOTE: These formulae just give the magnitudes. You need to determine the direction where appropriate. J = CE I = JA point: Um = 5% , Vpoim = ~K—q ’iz r K=mv2/2,’U=qV,AU=qAV ES=—:11—V S Q = C AVC , Uc = Q2/(2C) = C(Ach/z ‘ 2 -1 Parallel: Cam = C1 + C2 + Series: Cequiv = (i + i + ...) C1 C2 9 _AVR 2 2 Ohm sLaw: 1= R PR=IAVR =IR = (AVR) /R Pam“ l 1 '1 Series Rum = R1 + R2 + ‘Ségiks: Requiv = (F + R— + n) l 2 e=l.6x 10'l9c, mp=l.67x10'27kg me=9.l 1x10'3‘kg K=9x109Nm2/C2 Exarn2 Page 1 of 6 W is Q1. (20 pts) (a) (10pts) A 2.0mm—diameter plastic bead is charged to -l .OnC. A proton is fired at the bead. from very far away with a speed of 1.0 x 106 m/s and it collides head on with the bead. What IS the impact speed? .. 4“ : 0~Oalm yam" a T-— Lbrlo C. \q": ‘lxlo‘qc K‘, 6 v5: two ml; AKE a: «- AM __ I- «I‘;> 2 1 _ __ who‘ll Ho ”)0st _ O ‘ —- ~25 {)("‘7’Iv'”’<afi‘)iwz- C!»~c‘mis\1\. 4-» (“Wm ) . «I t‘.§§-w:>”?ka(Vfi)—- 11 F35» lo"""l<m1/fz ;. LKNHO ‘5 >.. 2.2775ylbdf : LBSXID" m/S ‘/ Q") 8.15" W” (b) (4pts) What is the change in the electric potential in going fiom very far away to the surface of the bead. C? , t? _ *4 _ 9W ba‘mj Av ‘: .EE: — O : /' (X I?" 3( lA' to > : ‘qmov KAOUnH‘D $9 éhlhfit \’ 0 ' 05,! 3; 8:34.33?— 7? réb/ 4A5 p “44- 4‘ l . col ‘7, ., 1 [on prowl; 6n 414.1 clam/aye 6i“ Hm {cu V02) rug-(- do _ “Hui Par-FHgCQ ‘Hxfi‘l' Rape/L45 4": be 9“; 4‘1,&JQ,,3,.J . (c) (6pts) Using the axes below, sketch the energy diagram for the system. I have already drawn the total energy of the system for you. Energy +5. {la/e. 35 am laid-{Al ILE am 4L4. (”04m 35 skrl’ MA as H‘ apploaclwfl) 4M Mlbowhyfi chart); o‘F‘ “Had- Léal) \+ ‘ ' a l 9- , “ 4 ', ‘ncfeasgs, (We 5 4 Mic O polw.a\ {Ne/3t) MINA Y" S V017 QM qwaw) bu; \‘l‘ XL'QMQS H)“ + 05 {4‘4 pro‘l'on ‘5li \t I, (“i/>6 > ‘ 133S°5X2b-d0° clas: “”4 r #2323223 {in nri' sum lnow 4'» JJZSL/Ilax +ku+ 1r“ «PM allay/4M. Q2. (20 pts) A contour map (equipotentials labeled in volts) is shown below. V Contour map (a) (6 pts) Estimate the electric field strength at a and at c. F $.31 :MEIV:!I.32V/m\ / -' AS /5-33im MW” ! r» A! xiii?” _- x, 2 WM. / a : O 5 : 0 ‘ 5% (b) (4 pts) Draw arrows representing the electric field at a and c, paying attention to the directions and relative magnitudes. (c) (4 pts) The is a missing equipotential that passes through point b. Using a dashed line draw and also label it. a (d) (3 pts) Rank the potential at points a, b, and c. (Example: Va> Vb= Vc. W > Va > Vb / (e) (3 pts) A proton (q=l.6 x10'19C, m=1.67 x10'27kg) starts at point d. What would be the change in its electrical potential energy if it moved to point e? AU :0 5th“ “HM Jisi‘o‘yxu imam +14 Sow/(,4; (Visual-t “Vt W —-P.7 Vetuiea‘i‘gmei-e‘ () WORM basicallb S+At3 umLH Afltygfl, "l I n ' ‘ . 133s05x2b.doc 'e 56“ L O 30132;} 0f6Q w/DNhWI QX (20 pts) (a) (9 pts) What is the charge on each capacitor? (b) (6 pts) What is the potential difference across each capacitor? C1= 4mg = 4mg = SuF (Please put your answers in the table below) ——-—_ chargeonthe _ 5' -g L —-S‘ _W w m u/ potential difference M _,__ V __ 5‘ / SV/ Owl Q : 45 MW :.- at...“ij than) C. / GH-Z ~ " 93 CD) ._ C) V 9r.- E1: ~ (We-NM "‘5 °2\/ — ZMDWCV 3 (32 AVl-fiz '- AV; / {v : 5V/ (c) (5 pts) What is the total energy stored‘7 1 M ? ~‘5 _ , C. M - 02 Mg; r"*g%flg“”igj - {IMO ‘5 5 ~ k“(Q2 L c 4‘ E? + 2( Mo 4 “l" M Mr; » ( we "I r /¥/0 (J POW/b") «q- 3 m Mr, 4- bit; (@4043 4' (I), It) " W . . l33505x2b.doc Page 4 of 6 Q4. (20 pts) (a) (6pts) The figure below shows equally spaced (by 1cm) equipotential lines. Calculate the magnitude of the electric field at points 1 and 2. i ll- 5 E 2i. E 2V 1V 0V -1V -2V -3V H 1cm (”l + 3\V . w ,— 59—y— ‘: :- lOD V m «3.331 _ [2”0"V«,~(/cx) WW I E1. '“ As (””5” / W (35 ‘ 0- 0an ’ / / (b) (6pts) The figure below shows equally spaced (by 1cm) equipotentials along a 1 mm diameter wire that has conductivity 0: 1.0 x 105 S2" m'l. Draw the directions of E, I, and i. (c) (8pts) Calculate the current flowing in the wire. E:A\1_(:lii}-‘i-. “DOV/M (3.5 ~ 0. oz M . fivmwwsfl ’5ng (We 1:234 55 ’I = 6’94 133505x2b.doc Page 5 of 6 5' Q3. (20 pts) V . . 1 :r In the figure all resrstances are m ohms and all emfs are [ C in volts. 8 F + 10 * (a) (12 pts) Apply Kirchoffs rules, set up the equations, ——- 10 V solve for the currents, and fill in the table. 5 V W Please indicate the magnitude and direction of the Q currents, e. . 4.2 A u. current through the left current through the middle current through the right batte batte batte O 3.75/4 6’0me 0. 25.4 MP/ [ZS/4. M10 AVADA4503 AVABATO: lO—loI“S'l°I 2011 , 110/ (wt 50"“ ”'5‘ ?01 p> 3,553.1} AV”; : o : ’0 —ME"0$ V '5’ : "VOI )\ + ‘l 5.27% {3.12.54 0 I?§ A “ I é‘fléflw («m-‘tfi’f—"ngm FT 0 ZSA (b) (8 pts) The circuit below has 4 identical bulbs. What hapeens to the brightness of Bulb A if you unscrew Bulb D? Does it increase, decrease or stay the same? Be sure to justify your answer. A I A )o— 31 ~ 3.31 6 {Avril --8371' c EA wHA bulb D ‘m plaw 92M. +0 (.05.: Cur/"4%, 15 LEEA W’MM‘l‘ bulb D m 63’4“ 133sOSx2b.doc Page 6 of 6 ...
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