13 - Work - Conservation of Energy For next time Read Sec...

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Conservation of Energy For next time Read : Sec. 7.5 – 7.8 Homework : Ch 7: 24, 26, & 34
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Energy • What is energy? – the capacity to do damage • What kinds of energy are there? – kinetic (associated with motion) – potential (associated with elevation)
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KE + PE = E v= 0 2 1 2 K Em v = take m = 1.0 kg
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KE + PE = E v= 0 0
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v= 0 KE + PE = E 5 m 0 PE = m g h ( ) ( ) ( ) 2 = 1 kg 10 m/s 5 m PE
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KE + PE = E v= 0 5 m 05 0 Now, release the ball.
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KE + PE = E v= 0 5 m 05 0 ?? ? v f 2 = v i 2 + 2 a y y 0 10m/s 2 2 fy va y =∆ ( ) () 2 210 m / s 1 m f v = y y = 1m v i = 0 v f = ? a y = 10 m/s 2 4.5 m/s f v =
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KE + PE = E v= 0 5 m 05 0 v= 4.5 m/s 10 ? ? 2 1 2 KE mv = () ( ) 2 1 1 kg 4.5 m/s 2 = 10 J =
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KE + PE = E v= 0 5 m 05 0 v= 4.5 m/s 10 ? 40 PE = m g h ( ) ( ) ( ) 2 = 1 kg 10 m/s 4m PE = 40 J PE
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KE + PE = E v=0 5 m 05 0 v= 4.5 m/s 10 40 50
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KE + PE = E v=0 5 m 05 0 v= 4.5 m/s 10 40 50 v= 6.3 m/s 2 fy va y = () 2 210 m / s 2 m f v = 6.3 m/s f v =
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KE + PE = E v= 0 5 m 05 0 v= 4.5 m/s 10 40 50 v= 6.3 m/s 20 30 50 Let’s check
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KE + PE = E v= 0 5 m 05 0 v= 4.5 m/s 10 40 50 30 v= 6.3 m/s 20 50 2 1 2 KE mv = () ( ) 2 1 1 kg 6.3 m/s 2 = 20 J =
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KE + PE = E 5 m 05 0 10 40 50 30 20 50 Question: How fast will the ball be traveling when it is 1 m from the ground?
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This note was uploaded on 04/13/2008 for the course PHYS 211 taught by Professor Shannon during the Spring '08 term at MSU Bozeman.

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13 - Work - Conservation of Energy For next time Read Sec...

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