18 - Conservation of Momentum

18 - Conservation of Momentum - For next time Read: The...

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Collisions For next time Read: The rest of chapter 9 in Serway Chapter 6 in Adams & Francis (posted on website) Homework: Handout from Adams & Francis Problems 3, 6, and 13
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Problem: dropped ball Drop 200 g ball from height H = 3 m. It rebounds to h = 2.5 m. What is p in collision with the floor? 2 i vg H = ( ) () 2 2 10 m/s 2.5 m 7.07 m/s == 2 f v gh = ( ) 2 2 10 m/s 3 m 7.75 m/s fi mm ∆= pv v ( ) ( ) ( ) 0.5 kg 7.07 m/s 7.75 m/s =− 7.41 kg m/s =+ (upward)
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Problem: dropped ball What is in the collision with the floor? t ∆=∆ Fp 7.41 kg m/s = +⋅ (upward) t = p F 7.41 kg m/s 148.2 N 0.05 s == F Need to assume a time: 0.05 s Compare to 2 N mg =
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Truck hits Volvo or, Volvo hits truck.
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During the collision What is the total impulse for the truck-Volvo system? Impulse = F t
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During the collision What is the total impulse for the truck-Volvo system? Impulse TOTAL =Impu lse TRUCK + Impulse VOLVO
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Free-Body Diagrams W E,T N R,T W E,V N R,V N V,T N T,V Impulse TOTAL =Impu lse TRUCK + Impulse VOLVO
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Free-Body Diagrams W E,T N R,T W E,V N R,V N V,T N T,V Impulse TOTAL =Impu lse TRUCK + Impulse VOLVO N V,T t truck N T,V t volvo
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This note was uploaded on 04/13/2008 for the course PHYS 211 taught by Professor Shannon during the Spring '08 term at MSU Bozeman.

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18 - Conservation of Momentum - For next time Read: The...

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