ee101_hw1_fall06_sol

ee101_hw1_fall06_sol - EE 101 Homework 1 Fall '06 Redekopp...

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1 EE 101 Homework 1 Fall ’06 Redekopp Name: ____SOLUTIONS________________________ Lecture 9:30 / 12:30 / 5:00 Due: Score: ________ Show work to get full credit. Remember, use on only one side of the paper and staple them together. Only use a calculator to CHECK your work, not to DO your work. 1.a 1100101.1011 2 = 1*2 6 + 1*2 5 + 1*2 2 + 1*2 0 + 1*2 -1 + 1*2 -3 + 1*2 -4 = 101.6875 10 = 001 | 100 | 101.101 | 100 2 = 145.54 8 = 0110 | 0101.1011 2 = 65.B 16 1.b 1A9.D 16 = 1*16 2 + 10*16 1 + 9*16 0 + 13*16 -1 = 425.8125 10 = 1 | 1010 | 1001.1101 2 = 110 | 101 | 001.110 | 100 2 = 651.64 8 1.c 617 8 = 6*8 2 + 1*8 1 + 7*8 0 = 399 10 = 110 | 001 | 111 2 = 0001 | 1000 | 1111 2 = 18F 16 2.a Following Generalized Integer Method and Fraction Method, we have: 97.8125 10 = 1100001.1101 Integer Quotient Rem. Coeff. Integer Fraction Coeff. 97 ÷ 2 = 48 1 a0 = 1 48 ÷ 2 = 24 0 a1 = 0 24 ÷ 2 = 12 0 a2 = 0 12 ÷ 2 = 6 0 a3 = 0 6 ÷ 2 = 3 0 a4 = 0 3 ÷ 2 = 1 1 a5 = 1 1 ÷ 2 = 0 (stop) 1 a6 = 1 0.8125 × 2 = 1 0.625 a-1 = 1 0.625 × 2 = 1 0.25 a-2 = 1 0.25 × 2 = 0 0.5 a-3 = 0 0.5 × 2 = 1 0 (stop) a-4 = 1 (97)10 = (1100001)2 (0.8125)10 = (0.1101)2 2.b Following Generalized Integer Method and Fraction Method by using base 8, we have: 1337.625 10 = 2471.5 8
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2 Integer Quotient Rem. Coeff. Integer Fraction Coeff. 1337 ÷ 8 = 167 1 a0 = 1 167 ÷ 8 = 20 7 a1 = 7 20 ÷ 8 = 2 4 a2 = 4 2 ÷ 8 = 0 (stop) 2 a3 = 2 0.625 × 8 = 5 0 (stop) a-1 = 5 (1337)10 = (2471)8 (0.625)10 = (0.5)8 2.c
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This note was uploaded on 04/15/2008 for the course EE 101 taught by Professor Redekopp during the Fall '06 term at USC.

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ee101_hw1_fall06_sol - EE 101 Homework 1 Fall '06 Redekopp...

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