# HW6_Solutions - c = 304.2 K, P c = 73.83 bar, ω = 0.224 Z(...

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CHBE 321 – Homework 6 – Spring 2008 5.39 (b) T 1 = 450 K, P 1 = 5 bar, T 2 = 376 K, P 2 = 2 bar, C p /R = 4, T σ = 300 K Δ H=-2461 J/mol Δ S = 1.64 J/mol K -1 W s = -2460.9 J, W ideal = -2953.9 J, W lost = 493 J, S G = 1.643 J/K 1

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6.14 (e) Carbon dioxide at 325 K and 60 bar T = 325 K, P = 60 bar, T

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Unformatted text preview: c = 304.2 K, P c = 73.83 bar, ω = 0.224 Z( β ,q) = 0.729 HR i = -2.3×10-3 J/mol SR i = -5.024 J/mol K-1 Compare these results from those found using the Virial Equations of State 3 4 From Table F.1, T 2 = 384 K 5 6...
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## This homework help was uploaded on 04/13/2008 for the course CHBE 321 taught by Professor Hyunjoonkong during the Spring '08 term at University of Illinois at Urbana–Champaign.

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HW6_Solutions - c = 304.2 K, P c = 73.83 bar, ω = 0.224 Z(...

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