HW7_Solutions

HW7_Solutions - 4 5 6 7.19(a) Operating conditions: T 1 =...

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CHBE 321 – Homework 7 – Spring 2008 1
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6.87 (a) 1,3 Butadiene at 500K and 20 bar: T c = 425.2K, P c = 42.77 bar, ω = 0.190 Æ T r = 1.176, P r = 0.468 Use Virial Equation: 0.083 B0 = -0.242, B1 = 0.052, DB0 = 0.443, DB1 = 0.311 VR = -191.99 cm 3 /mol , HR = -1.164 × 10 3 J/mol, SR = -1.952 J/mol·K -1 3
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7.5 Calculations may be carried out for a series of exit pressures until a minimum cross-sectional area is found. The corresponding pressure is the minimum obtainable in the converging nozzle.
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Unformatted text preview: 4 5 6 7.19(a) Operating conditions: T 1 = 450C, P 1 = 8,000 kPa, mdot = 80 kg/sec, P 2 = 30kPa, = 0.80 Intake conditions: H 1 = 3274.3 kJ/kg, S 1 = 6.5597 kJ/kgK-1 , = 0.80 Discharge conditions: S liq = 0.9441 kJ/kgK-1 , S vap = 7.7695 kJ/kgK-1 H liq = 289.302 kJ/kg, H vap = 2625.4 kJ/kg mdot = 80kg/sec Isentropic S 2 = S 1 H 2 = 2423.9 kJ/kg S 2 = 7.1808 kJ/kgK-1 Wdot = -68030 kW Wdot = -91230 hp 7 8 9...
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HW7_Solutions - 4 5 6 7.19(a) Operating conditions: T 1 =...

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