This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: Engineering Circuit Analysis, Tm Edition Chapter Eight Solutions 10 NIal'ch 2006 54. ‘VA 2 600m{r+1:}v. v3 2 6000 +1) now, I; = 6(r— l)rr(f— DA (:1) r = —1.5: :1 = 0; z: —0.5: fl = seer—0.5) 300 = s‘ a 300 3
4 'ns
(21.5:f1=%+%—éx6x05=3+5+1 (b) PROPRIETARY MATERLLXL. '1C 200? The McGrawHill Companies. Inc. Limited distribution permitted only to
teachers and educators for course preparation. If you are a student using this Manual. you are using it Without permission. Engineering Circuit Analysis, Tm Edition Chapter Eight Solutions 10 NIal'ch 2006 (a) :1 {1) 2 2+ 20 —e3 “mm A r1905.) (b) s, {0.5) = 2+ 2 (lie—1'3”) = 3.42%. (c) i. {1.5) = 2 + 2 {1—e31‘) = 3.953A PROPRIETARY MATERLLXL. '1C 200? The McGrawHill Companies. Inc. Limited distribution permitted only to
teachers and educators for course preparation. If you are a student using this Manual. you are using it Without permission. Engineering Circuit Analysis, Tﬂ' Edition Chapter Eight Solutions 10 Rialch 2006 63. (a) I". (r) = (4 — dorm""1"2 mm (b) m1)=(100—809‘100D’)u(r)v ‘m    34;; E
x 83
x \ «m: M B n 0.5 1 1.5. 2 2.5: a 3.5 4 «1.5 5
‘63 MU PROPRIETARY MATERIAL. Q 2007 The McGrawHill Companies. Inc. Limited distribution permitted only to
teachers and educators for course preparation. If you are a student using this Manual. you are using it Without permission. ...
View
Full
Document
This homework help was uploaded on 04/14/2008 for the course EECE 112 taught by Professor Fitzpatrick during the Spring '06 term at Vanderbilt.
 Spring '06
 FITZPATRICK

Click to edit the document details