HW 27 Solutions

HW 27 Solutions - Engineering Circuit Analysis Tm Edition...

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Unformatted text preview: Engineering Circuit Analysis, Tm Edition Chapter Eight Solutions 10 NIal'ch 2006 54. ‘VA 2 600m{r+1:}v. v3 2 6000 +1) now, I; = 6(r— l)rr(f— DA (:1) r = —1.5: :1 = 0; z: —0.5: fl = seer—0.5) 300 = s‘ a 300 3 4 'ns (21.5:f1=%+%—éx6x05=3+5+1 (b) PROPRIETARY MATERLLXL. '1C- 200? The McGraw-Hill Companies. Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual. you are using it Without permission. Engineering Circuit Analysis, Tm Edition Chapter Eight Solutions 10 NIal'ch 2006 (a) :1 {1) 2 2+ 20 —e-3 “mm A r1905.) (b) s, {0.5) = 2+ 2 (lie—1'3”) = 3.42%. (c) i. {1.5) = 2 + 2 {1—e-3-1‘) = 3.953A PROPRIETARY MATERLLXL. '1C- 200? The McGraw-Hill Companies. Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual. you are using it Without permission. Engineering Circuit Analysis, Tﬂ' Edition Chapter Eight Solutions 10 Rial-ch 2006 63. (a) I". (r) = (4 — dorm-""1"2 mm (b) m1)=(100—809‘100D’)u(r)v ‘m- - - - 34;;- E x 8-3 x \ «m: M B n 0.5 1 1.5. 2 2.5-: a 3.5 4 «1.5 5 ‘63 MU PROPRIETARY MATERIAL. Q 2007 The McGraw-Hill Companies. Inc. Limited distribution permitted only to teachers and educators for course preparation. If you are a student using this Manual. you are using it Without permission. ...
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This homework help was uploaded on 04/14/2008 for the course EECE 112 taught by Professor Fitzpatrick during the Spring '06 term at Vanderbilt.

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HW 27 Solutions - Engineering Circuit Analysis Tm Edition...

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