hwsolution9_pdf - lin(gdl353 Homework 9 shubeita(58390 This...

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lin (gdl353) – Homework 9 – shubeita – (58390) 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001(part1of2)10.0points Given a current segment which flows along the edges of a cube as shown in the figure. The conventional Cartesian notation of ˆ ı (a unit vector along the positive x axis), ˆ (a unit vector along the positive y axis), and ˆ k (a unit vector along the positive z axis), is used. The cube has sides of length a . The current flows along the path A→C→D→E→G . There is a uniform magnetic field vector B = B ˆ ı . x y z B B B A C D E G a a Find the direction hatwide F vector F bardbl vector F bardbl of the resul- tant magnetic force on the current segment ACDEG . 1. hatwide F = 1 2 parenleftBig ˆ ˆ k parenrightBig 2. Undetermined, since the magnitude of the force is zero. 3. hatwide F = ˆ 4. hatwide F = ˆ k 5. hatwide F = ˆ correct 6. hatwide F = ˆ ı 7. hatwide F = ˆ k 8. hatwide F = 1 2 parenleftBig ˆ + ˆ k parenrightBig 9. hatwide F = 1 2 parenleftBig ˆ k ˆ parenrightBig 10. hatwide F = ˆ ı Explanation: Note: The force on wire segment AC is canceled by the force on wire segment EG . The current in wire segment CD flows in the ˆ ı direction and the current in wire segment DE flows in the ˆ k direction. x z A G a a TopView B B B ˆ ı ˆ k ˆ ı ˆ k B B B The magnetic force on a wire is given by vector F mag = I vector × vector B . The vector vector is given by the sum of the current segments vector = −→ AC + −→ CD + −→ DE + −→ EG , and this is the vector −→ AG , (see figure above). The magnitude is given by vector F vector × vector B ı ˆ k ) × ı ) = (ˆ ı × ˆ ı ) ( ˆ k × ˆ ı ) = 0 ˆ hatwide F = ˆ . 002(part2of2)10.0points Find the magnitude bardbl vector F magnetic bardbl the magnetic
lin (gdl353) – Homework 9 – shubeita – (58390) 2 field exerts on the current segment ACDEG if the. Magnetic field is 1 . 78 T, a is 3 . 81 m, and the current is 5 . 14 A. with the vertical when in equilibrium ( v = 0 m / s), determine the strength of the magnetic field. 003 10.0points If the wires make an angle of 22 with the vertical when in equilibrium ( v = 0 m / s), determine the strength of the magnetic field.
A metal rod having a mass per unit length of 0 . 0424 kg / m carries a current of 4 . 9 A . The rod hangs from two wires (in the same plane as the rod) in a uniform vertical magnetic field as in the figure.

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