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Unformatted text preview: Chemistry 13022, 3
Exam 4
April 27, 2006 Name 11109110 M1166 9.00MWF ‘/ 11:00Mi1vri \lultiple choice Lpo oints each). Mark your answergn the scantron. Be careful to erase completely if you change an
answer. Only the scanlron will be graded. Check ou ans ers; don' t be careless! Show your work on the exam booklet 1. A+2B+C——’ 2D+E Experiments involving the reaction above yielded the following data;
initial rate (mol/L—s) [A]Q (mol/L) 1319 (mol/L) LC1Q (mol/Ll 1 R1 1.407 ‘ 1.40';\ 1.00 "11
2.112: 1/2 R1 0.70: 1.40 s 1.00
3 R3— 1/2 R2 0.70; 0.70 1.00 f 1m
4. R4: 4R3— 3:; 1.403 140" 0.5011: 11': 3‘17!
“1 I ‘1,
What IS the total reaction order? 3 C1393 lift "' I???“
A. 21/2 1 \ H . 9%
(E 2) I ‘ . M r \ I
C. 3 i K C (13%“ Li} "
D. 1 1/2 1 ‘ Lgyglp
E. 1 Q’— am ”1: .1 lizltﬂgfi
’1 {m :11“ 1 3“”71’M‘ ‘ ‘
3* :1 L": 1" 3" e0
1 C "1
I" 39.:
2. 2H+ + H202 + 31— *#—’ 13 + 2 H20 {(3% 15‘ L— Experiments involving the reaction above yielded the following data: L45 mm; mm initial rate lmol/L—s) [H203101m01/L) {I}, (incl/L) [11“10 jmol/L) 1. 1.15 x 10‘6 ‘ C1010j ' O00005011L ° “"5 2. 4.37 x 106 (0.01038 .010 f 0.;00050 “’ ° CW 3. 1.45 x 10'5 0.0104 0.1262! 0.0005011 4. 5.51 x 105 0.038 0.126 0.00960 What IS the meowge reaction? HS 1110“" KL ”.5114 L 013“ C 0096/]? A 1.15 x10 L/mol n P B_ 115101110121 mamS #1261131" C 1101 C «>133
—4 ,. . 1 1 ‘o 2 ,1" C. 2.30 x 10 /s \HSVMDFJ‘M? “/1 MM ‘\ 3 /; D 1.15 x 10‘5 L/mols ”J" .15 ’ 1 DU 1.571134“ ‘v'b‘ like XED *1 '  \
E. none of the above , ’ 51‘? m’ _ u ,q
51.51110 r" 1%»! >149" ~10qu 5 1" 1111241 11111199.. 31' 1 We ..
’ .— “41 ‘ . _ 7 ”p {006119 \e ‘ V 3. For the decomposition of gaseous dinitrogen pentoxide, \‘anﬁ ) '; “‘” Vet
J 39‘ D
ZNzostg) —’—“" 4N02(g) + 02(g) » the rate constant is k = 2.8 x 10'3 s’1 at 60 °C. If the initial concentration of N205 is
1.58mol/L, what is [N205] after 10.0 minutes? /  ‘ g A. 0.68M ‘0 CD ‘1, : 1.g_viujﬂ WW‘XCGO
. ‘ 1 l L D. 1.56M E. 0.42M 4. The gas phase decomposition of H1 ,2
2,9016% 2: 4% Jr 2 Hltg) ——' H2(g) + 12<g) =0
teequfi‘tionglﬁlate— — k[HI]2. The rate constant k, is 300L/mol—mi at 443 C. ow much time oes 1%” concentration of H1 to drop from 0 010 mol/L to 0.0050 mol/L at443 °C? , \ ,L.» ‘\ 1:,
(i 1\“’ mm“ :(090 'mnhxt A. 30 min to} .2 mal
00 3 6, 0‘
B 0.30 min L ) L’ j
C. 6.5 min £52 Y @LW‘M : 3'73'7Jw1‘n
m ml 1:
mf the above
W :NH”
5. The reaction S02C12(g) —"—‘“’ SOz(g) +C12(g) ; {93M
isj first order in SO2C12 Using the following data, what 1s the rate constant?
Wwe. 7121in
time is! Eressure SOgCl2 (atm 1 “Maj 2300 g
1. 0 1.000 in (""3” “4 “‘4 (1 >
2. 2,500 0.947 23 l
3. 5,000 0.895 [(2 2 1‘?) 3:31;)”
4. 7,500 0.848 S
5. 10,000 0803
A. 8.9 x 10'3 Is 
B. 1.1X102/s
C. 1.83:1,05/5
{1); 2 2 x10'5/s} E. 1 none of the above ’i 7. 8. The decomPositlgnjeaeaeP, 2 N205(g) _’ 4 N02(g) + 02(9 has the rate equation: 1Rate  k[N205]. E/igﬂpggcgegt of the N205 remains after 6.0 h at 300K. hen e at 300m, .33.. Mater .
(A. with m(£9_%:b ﬂijtgw‘) f:
\00 B. 2.6h C 7 0.27 h 0 o 43"! 3.1;
D. 0.037 h
E 15 h h  £2,939.22.
{ i 'L I XL, R I
For the elementary process, N205 (g) —* N02(g) + N03(g), the reverse reaction activation energy (Ea ) and overall are18 kJ/mol and 136 kJ/mol, respectively
What 13 the activation energy for the forwar reaction? A. \«290kJ/mol AH AH A019 irxo’r We? eyganJ CV3
Nitrosyl bromide, N OBr, can be made by treating nitrogen monoxide with bromine: 2 N0(g) + BI2(g) —" 2 NOBr(g) Experiments involving the reaction above yielded the following data: M \‘q’ * ’ “ .1319; wmmowmrﬂomgm 1 24 0.10 1. 0.20 ‘ Li ‘W99 2. 150 .25 0.20 1.1 X10 3. 60 .10 0.50 4 735 0.35 0.50 met 0k . m W O¥€ 1,4 1 (.l0\ L;5 m
1°50 .153 ., 4L0 ”LL41,“ M31 B. 11.21 .2 7940'}:mele . . 2 n G’WBO—MBS‘W/moPs £99 ”I @231, 31:...“ 13.1.... 12.x 104umo1—s 1515 (.131 a3 ' E. none of the above ”WWW 1,. a mix"
it meet/k, Which is false for a balanced elementary process equation?
A 1/ Unimolecular and bimolecular processes are more likely than termolecular ones.
B./ Elementary processes may be reversible. if/C‘ {l {5 S I C. \/ The slowest elementary process in a mechanism is the rate determining step. D. y/Rate law concentration term exponents are the same as stoichiometric coefﬁcients E None of the above statements is false purify D 19613 “$551215; \C :1 was 1;; 11 item/b 10. In the reaction, A ~——,’__ products, the fOHOV in0 data are obtained: t= 0s, [A]: 0.88M 1255, 0.;174M 50s 0.62M; (755, 0.5%52M11005 044M ‘1‘.” w_.w 125 s, 0.37 ,in, 150 s, 0.31 M What 13 the instantaneous rate oij reaction at t: 125 s? g, Aaassc—ieiM/s 1, , (is ,1, , 1
é Bwas M/S' ’i’j , w; .00 S? to ”‘4 82 0D 1L;
OQAI/ Cw;. .4 2x 10’: M/s :1 15 3'5
(D 2.61110“ M/s> _ W \ W“
E. Not enough information Is given to answer the question.
“Ea’V/‘t "$.130" ”0' 90‘4”!)
“1%: degassEm As (71%” ¥~ i: A3“
' S ”1 ?%:»1.1sr1 1121100" (011110113
' Yea7”} [11113127. 111111: ‘5 11. The gas phase decomposition of 7N02 at 383 C, gives the following data. V 12. In the reaction, A w products, the fol]
exp. 1 [A}O : 1.00 M, t1”: 50 min 0.10%
exp. 2 [A10 2 0 50 M, tm _ 25 min [Cr/q," W
exp. 3 ML: 2. 00 M owing data are obtained: , stant for this reaction?
A.,,;::.0.02.0. 111 7 ”of w! ~
mu . L we x I. 0‘ a 1,, in.
\B' ‘ 0.010 moi/Lfmm “1 L m“ A ' f ’LL 7
W133i ~m1n * " vi" “5:. I, 02
X/L' t fl "'— o
D. 0 010 L/mol~min F A—
. b
Et—"N6Te‘nough information Is given to answer the question
. ,, An:
Awe L .. _._...
a (0351 ’L t
13 For a zero order reaction What f four haif— lives ‘2 i ,
1 » _____ 1 ”‘ PM“,
A. one—half {5:1 1  3, 3:; 2 :9 w“
B. onefourth { 3.! M45“
C. one~eighth <1 :3 \ \ .5 1 ,L
onesixteenth ' a ‘Q MM. ‘ w
E. . 14. For a zero order reaction, A N products, a plot ofC versus 15
linear. L '( . "a “7..
,, D} (0091 2 N'z/OGA
t .1 ., I}; [2,,
E. none of the above Q“
15. The followmg mechanism has been proposed for the gas phase reaction of H7 and NO to
produce N7 and H20 "Va
2 NO ”ﬁ— W—M— N2Q73t~n   aﬁasggguilibnum
(Hz/+3120; N N20 + HcO E193...) N2 4L H20 ‘ “““““ fast
It is possrble to predict the rate expressron and show that the total reaction orderls
g 1 am i» an waL 4: :wlo 17. If the mechanism for the reaction Hm) + I2_(g) “H 2 HI'rg) is I204) 2/1?gi fast equilibrium e apparent overall order for {.3121 (”e“'13” ’5” :1E
”IL 9
' T " E.
3} l: 1 H2
fr; — TH; C204'2 4* 2 HgCIz M 2 C0; + 2 Cl‘1 + HggClz
Experiments involving the reaction above yielded the following data: initialrategmollL—min) ‘ [C204'12]0 (moi/L! IHgClg]D (mol/L) 1. 1.8x 105 0.15 2, 0.104~ ‘ l
2. 7.2 x 10'5 0.30 . 0.104 3. 3.6 x 10—5 0.30 . 0.052 4. X 0.21 0.020
What is the value of X in experiment #4? W «.5 Va
Livro'w820wxiﬁ'3’ 333,523. : . 3 L3 ‘; 2m {23; I If the mechanism for the redox reaction ' ng2+ (aq) 19. A sample of uranium was found to have 0.72 % 73
ago did the sample contain 4.0 % 23
reactor. The halfulife for uranium— 5U. (A. 4,5210% ii: 0'19“?) B "”.;§:57X:1087 :ﬂghihaq‘g L"
(MAJDES D "1.5x108y m (3:1. : _. K—@
E. ‘ 1.5 x109y ‘03» 20. A
A A 10 ears ”‘3
B.V‘__<,}123§:ears ;n( «w E “a: Z) 0T1
ﬁf‘ﬁfyaarg """" " i
E. 25 years 00mg},
{1: w ........ n
1: '3 [an 5U, a level high enou
235 = 7.04 x 108 years? involving an aqueous solution of Hga2+ and Tl3+
is as follows, A Approximately how many years
gh to sustain a natural nuclear €1.8"Yw'm
.12; w w i:
in :00)" L .15 came"? 21. 22. 23. Boron—12 is a radioactive isotope. Predict the decay mode. m 1m 1.. €)_ . m; l :LE _.,_7 (H HQ” W* $9.,"
C. positrononly ti ;2 b . L . . » .. .
D. ,ezeaptureonlym .1 1‘, 5 (3‘ 1. t1. ‘.
E. ‘ either positron or e—capture SE7 '7 F t a LG ,1"; i ' 2) lb 1’; {b 7 g t H Em A sample containing Ra—224 decays by 0: emission and is observed to have the following
disintegration rate in dpm (disintegrations per minute). At t = 0 (ﬁrst observance), 648
dpm; at t = 3 hour, 633 dpm; at t = 12 hours, 590 dpm; and at t = 18 hours, 563 dpm. When
will the activity have dropped to 25 % of its initial Value? A. 87 hours ln (“7333 —; v \Q (’5 hr)
B. 133 hours 2%? 7 \ (a)
C. 167 hours lb 7' U .001 “8 1T
D. 172 hours
0 m 2a,) y at t:
w z ,
t t {37 1 L9 The age of some rocks can be determined by the ratio of the number of atoms of 206Pb to
the number of atoms of BSU in the rock (assuming that all of the Pb206 comes from the
decay of U—238). The age determined is when the rock solidiﬁed. If the ratio of atoms of
206Pb to atoms of 238U in an igneous rock is 0.33, what is the age of the rock? I0 (t 1,2 for mU = 4.5 x 109 years) 2})”, my 132% j :37 l) . «3’73 1, \ [km—ﬂ years ' a .L— B._§.~2».9~x , years L 9A9 (333 k L6H X10.— (5/
r“ M 9D; 1.9 x109 yeéﬁ\
E.;~‘:;;r+5~x—109years’ 1‘.“ 3;» \ ~«_, “‘ if" "(V
(L035! {: __ \‘E'CQYiOO‘ u. '1 1W! 8E — 328i is‘ an unstable inuclide. Predict the stable isotope which resﬁl’es fro"‘
sequence starting with silicon—32. A WW2” 93?}: ”A Lf M JV” 1?
i B. magnesium—28
/ Dir” sulfur3B '53 , O 3,; , i .
W“ W e r E. “43‘ \ .. (5 +* 36 PLFCMtDCt neon—24 I; V reg; x o a) e e M New
3&5 M (q; “”1 ! 3 Kb .
lv 4 i J
E m 333; 3 gm «r .4
‘5 9‘ 3 3;. I i
359$; * 1% a; mag
25. The age of some fossils can be determined by the ratio of the number of atoms of 87Sr to
the number of atoms of 87Rh in the fossilized material. If the ratio of atoms of 8731~ to
atoms of 87111b in a fossil is 0.0549, what is the age of the fossil? 3 (t mforszb=4Bx lawyers) , «315v 6:0
A. m y 2e B. 2.7 X 109 years /1,
(”CW7 x' ears mm
D. 1.9 x 1010 years
(«LE ) he f6 2.2x 10“ years 0 (9% 9H msyro'” \ V L“, M. 0 _ 2; ‘ I ‘\ L ‘Z'ZL‘OOQ'L (wuuaamama 'srn aw mama's 'uu’ 19d ‘9“): OlLDHH/G SlHi 033:1 ——‘> El S‘HSWOLSHU Elma NOILVHBdHOO‘ llllllrllII 401019qu 1 I ‘ .n .L —l
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