{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lab 1 - a.01 uF capacitor We used a function generator to...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Caleb Simms Electronics Lab 1: Resistors and Capacitors In part one of this lab, we set up a voltage divider using a 10k and a 5k resistor. V in is 15V supplied by the breadboard and V out is measured by a voltmeter. We measured V out to be 5V. The predicted value is given by V out = (R 2 )/(R 1 +R 2 ) is 5V so that matches. Then we “loaded” the circuit by placing a second resistor in parallel to the 5k resistor. We measured the values of V out for 100k, 50k, 10k, 5k, and 1k resistors. V out was greater for higher resistances. This justifies the statement that voltage sources like large resistances but it does not explain it. Voltage sources like high resistances because all voltage sources have an internal resistance and higher resistance in the circuit allows the voltage source to be more efficient. In part two, we dealt with high and low pass filters. In the circuit we placeda 10k resistor and
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: a .01 uF capacitor. We used a function generator to create a sinusoidal V in with peak to peak amplitude of 10V. We ran both V in and V out through an oscilloscope. We then measured the amplitude and phase difference of V out for frequencies varying from 1/100 th of the cutoff frequency to 100 time the cutoff frequency. The cutoff frequency is predicted by the equation f o = 1/(2 RC) which in this case was 1.59 KHz. Our graphs show that around the cutoff frequency is where the voltages first begin to change. With the low-pass filter, once you get above f o , the higher the frequency the lower the amplitude. With the high-pass filter it is exactly the opposite. Once you get below the cutoff frequency the amplitude begins to shrink. This is exactly what we predicted would happen....
View Full Document

{[ snackBarMessage ]}