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Unformatted text preview: W 7 March 2007 CODE # 1 1:00 pm. — 1:50 pm.
PHYSICS 114
Third Hour Exam INSTRUCTIONS: Answer each question. All questions carry equal weight. You should calculate your answers to three (3)
signiﬁcant ﬁgures. Your answer may not agree exactly with one of the possible answers, but your
answer if correc should a ree with one of the ossible answers to at least two 2 si iﬁcant ﬁgures. Be sure to enter the code number found in the u er ri ht corner of this a in the a ro riate
box in your scantron answer sheet. All information supplied by you on your scantron sheet must be left
justiﬁed, that is it must be entered beginning at the left hand end of the entry box. 1 Consider a planet which has three times the mass of the earth, but the same radius. With g being the
acceleration at the surface 1' the earth due to gravity the Wﬁonp du to gravity at thes ace ofﬂ
”W W thisplanetis WLML I15 EWW acm (20g Md)
=? (b)3g F61 611/513“??? ivy—WM =3 7; @2290. SW ,
(0) 1/3g 1;“ H ,1:  “I, (d)9 Owl/111191 MSW /1 3’1): ‘1 I» 3 H1? 51
(6)59 10 W M61? 21’ 17 2. If a satellite has a circular orbit of radius r, and period, T, about the earth, then a satellite in a circular orbit about the of no 8T, willha anobitalr diusW of M
11111:: MM 111W W % (190.251 F 11111,” mn agrfhu 4%”) ring 111.1;
(°) 8’ ﬁgﬁ: A :31? 111% r’ T MW “WW WM
(d) r/8 9 /9 [If 9 8.9.21, tj 7:1: 87 0/111, 01:90:
:> (CW :1 ~1£ _ r rL 611 mm
H? TL e r = 11641 1; L111" 3. The Earth has a radius, TRE, and a mass, ME.A body of mass, m, is located outside the earth at a '
distance, d, from the center of the earth. Apart from the gravitational constant, G, the acceleration of this body due to the gravitational attractionfzif the earth depends M l
(a) onlyonMEandm m E : 6115 = 1 1
(b)onlyonREandd ”‘6‘ ”4’3 ’4 4 6 119111 UL
(c) only on ME and RE m
(d)onlyonmandd J 1 W 111x111: “#140{ “Md" G $ (e) only on ME and d ’15 4 A porter carries a body of mass 37. 8 kg, to the top of a mountain of height, 4.27 X 103 m, above the
de arture int. The minimum work to a m lish this is
P I” P 41% 111031“ ‘1 3 113: a9(a)1.158x106 WWMC ago—1:
(b)2.17X106J 111“:th +1111: MAMMWMMCBO (c)4.55X10:J 111:: 111:1, : W
$333136} 1111114110» Max:005 9511 W with WAD OM11 O
:5th MW! WI“) ”41%;??37148011/1x41W/M aw“: 15‘6111114J: mxw‘] Phsxll4 sp07— —Exnm3_ e], Page 1 of3 W 7 March 2007 CODE # 1
1:00 pm. — 1:50 pm. 5. A commercial aircraft has a mass of 1.27 X 105 kg. It starts from rest and reaches a cruising speed of
3.07 X 102 m/s at a height of 1. 17 X 104 m above its take off point. Ignoring the effects of any
frictional forces, the m umwork do e by the engines of “this aircr this pro; ess is U’
WW 3? (Mg/0E0 FoﬁﬁL [51:11: Fm (a) 1. 46 X 1010 J Wm: M56546!) PE: 105
(b) 2. 78X 101° 1 mi}, :Jiml/o“ = *le “93 =0 M0 “ WWW 3), (c) 205x 10101 :7 WM — WESWE r—k ww + Mk
(d) 105x 10“ J 9M»: MEMO? XQ (man Mk)? WW 0
(6)5.9sx1o J & [01M mtg low 1430 “(m/d A
1111“wa _
205114th ”J :20? L C 02, 6. A roller coaster starts from rest at A and travels past B and then moves y
up to C. Point C is 23.6 m above the level of B. Assume that no work is 1 done throughout by non conservative forces. When the roller coaster
reaches C it has a speed of 15. 7 m/s. The height of A above B is wmvo q E:WWMWW O  (a)57.4m MSW ‘{ _,Zjém mam/1 (711:0 B
983% EF 56 =9 1W1 ”Wk ‘ JW‘ “”77 (d)41.6m 21mm + Mid/1:41am ””ch =7 (/yt = WELMVLLnLﬂ/Wc] _ 160 VIA (e) 32.8111 :3 — Ezk (ail/9 +29 6111: ItWéwH). {m 16' 7“ 1‘“? 1x4 8011/1 3___6 2m (M) 7. A body of mass 11. 9 kg IS pushed a distance of 18. 6 m up an inchne of 8. 62° The coefficient of 0t
faction between the body and the incline 15 0.262. The mi namuﬂwork needed to accomplish this is v1“? Mwmwlmn L lv
(a)4.62x1o:J§r FN zFaa/JB math 0 Ni: m: AMWB a; /
(b)325X10:J 2:1ij 1:;me “a :nlﬂx ~0 (an: DMWB) F %
2829112131ng efpff" smE +F swim/119mm?“ ”752119me ’6 F1119
(e)6.72X102J J=)Fp :fmg [sm9bét W W}; 1“ ‘1 :3 WI); #11413”? tug/197 :ZWPML 0 at 88+ 0251011884001: 15 7x10? C34“)
8. A race car :ogmass 9 5 kg accelerates from rest to a speed of 55.2 m/s 1n 3. 82 s on a level horizontal
surface. Ignoring the effects of all ﬁ'ictional forces, the average power developed byo the engine of this caris WM»: 0K5 'USPE AWE: PE p50: 5914/2 y: 50L
(a)8.55X10“W W116: ME 1019— We ”0‘0 “> 1450 FEW/a vtmxo :0 aamwxmsw MHKE: fmlr «Laiféfxﬁ'fLM/i) <c>6.86Xl0‘W p: wm  W 1651151 x10 w 41110101 34 (d) 4.28 x105 w T
(e) 4.83 x105 w L 3 $21 9. Water ﬁ'om a hose lS sprayed on a wall at a rate of 8 52 kg/s The water travels horizontally with a velocity of 15. 7 m/s. With res ect to the direction of the water, the force exerted by theo wall on /theg
We“ MAM/um F=%€ WaZMWb/m; 1 (a) 1.57X102N =11; U": W [0me :XM (7D: v1 (b) 2.67 x102N A (c)2.85X102N 2) 92513111459 iy‘ﬂgﬁ = 41376440 :«lWWO U MU __Oa/1 1km
(d) 1.34 X IOZN (e) 1.14 x 102N
Phsxl lA~sp07—Exam 3_cl, Page 2 of 3 W 7 March 2007 CODE # 1
1:00 pm.  1:50 pm. 10 A railroad wagon, of mass 1.17 X 104 kg is moving along a horizontal track with a velocity of 1.54 m/s 1n the direction of the +xaxis As this wagon passes under a hopper 2. 97 X 104 kg of coal lS dropped into this wagon. No unbalanced external forces act on this system throughout this process. \ The ﬁnal velocity of the wagon, together with its load of coal, is ”t :1.» W190? We (“wHM! Wm 1» 111m M1 ~ Vow CV2 1 (a) 1.06 m/s with respect to the +xaxis 275% yo ,3 [31):0 :5 (’3:
(b) 2 79 m/s with respect to the +xaxis _ 2 (c) 0. 435 m/s with respect to the +xaxis i)” ‘ MWUW + m‘ #06 "MW; H7005 “am???“
(d) 0.560 m/s with respect to the +x—axis p @1111 +1111 )VM 1; ho  (’1 €314“) W ll) ‘— <e>° ,1 +11: ,1. 1 1
~ I 11111 X H 0 Wﬂtﬂ 1155111
11 A golf ball, of mass 0.045 kg, 18 initial}; [at rest and is ven off the teeVvéithﬁg veibc mfg in  i
the horizontal direction. Assume that the time of the collision between the ball and the club is 3.56 X 9%
10‘3 s and that the golf ball travels horizontally at all times. With res ect to the initial direction of j
the incident ball, the average force applied to the ball by the club is 0mm 41111 km 9
5(a)7sox1o2N _ 91?“ F m.) 1 M . MirMUD 1L0 LL
é(1;)9.N77x102 EM: ' 6 ‘5 M7 :0 2 A 111111.10 : Mu 29mm : If W
(e) 4.85X10N 4 5% A (d) 152x 103N (e)9.277X10N 31% 0001111115]; ”111,0 iw‘HMWDU rim 541i 3 5?) W
12. A cannon of mass, 3.86 X 103 kg. 15 initially at rest when a cannon hail of mass, 32.7 kg, is ﬁred from
it. The muzzle velocity of the cannon ball is 142 m/s in the horizontal direction. With respect to the direction of the velocity of the cannon ball, the recoil velocity of the cannon is,
WWWW M1=W76dym1mlm 5V“ W W
(a) 149 m/s ____ % O
(b) 2.55 m/s W 4W D o a
(c)1.33m/s 21:an 2’) {F111 4‘“ WWW“) ‘ 1L
(d)—255m/s _) [0: #0 We @5111! u’: 0145111de :0 V“ O 1.
29(e) 1.20m/s i5: "‘an WNW b0 :0 :3 MM: #1350; MW LN/l 6
1.  1111/ 135% 51011111:
0‘0 m 71861810: _ MD Ms W) Phsxl l4sp07—Exam 3_cl, Page 3 of 3 ...
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