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Solutions for Exam 5 - Spring 2007

Solutions for Exam 5 - Spring 2007 - W 11 April 2007 CODE 1...

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Unformatted text preview: W 11 April 2007 CODE # 1 1:00 pm. — 1:50 pm. PHYSICS 114 Fifth Hour Exam INSTRUCTIONS: Answer each question. All questions carry equal weight. You should calculate your answers to three (3) significant figures. Your answer may not agree exactly with one of the possible answers, but your answer, if correct, should agree with one of the possible answers to at least two (2) significant figures. Be sure to enter the code number found in the u r ri ht corner of this a in the a to riate box in our scantron answer sheet. All information supplied by you on your scantron sheet r_nu___st be left justified, that is it must be entered beginning at the left hand end of the entry box. 1 A body 1s suspended by three cords as shown The tension, FA, is 75 7 N and the angle (p is 54. 9". The mass of thrs body 1W I t W 314/!th L- __ farm 4%}41W (a)5.09k . at O FEW EA - Wilmer: §§*-$’Zwl”%”¢ 019—me @ w c g W‘[email protected](d)5-_43kg 4m :F‘M‘L‘b WWQ m W%W/l MW (e) 6.17 kg :lm m ‘%%= 2 A massless beam of l 4 79 m, rests on a support at C, as shown. A body of mass, mA — 57.4 kg rests at A and a body of mass, mB= 28. 6 kg, rests at B This system is in equilibrium if 1— — MW “1m. (a)l.88rn ZQWQ 55% vajMflggm/léo O 5 WU” aggljzgwa asmté‘ila Wt MM mot-o L g W11“? (d)l39m :Almkgtmmfi; ”‘93 W- (e)1.42m :31 mag: Lmn C 13 yawn) MW]? 3. Auniform beam 0th ass, m— 123 4 kg, and length, L= 5 14 In rests on two supports, A and B, as shown. A force, F= 376 N downwards, is applied at C. The am will instT tip if 1— — (a)1.17m Tfifo’MA/m WWW WWW FF LO/th b (41141} 288.334: itgrwjm Amigslwflw ~ 1995101440 0 P1 ((1)0882me syn U=l (Eammifi TF1 m TF3 4. Auniforrn beam, AB, ofrnassf m= 927 kg, and length,L— 17.,6m supportsamass, M=l. 17X 104 kg, atC which rsadrstance 1’1497mfromB. The (:6 exerted by the support atAon the beam rs WIW):>(a)369X104Nupwards 1 WanW W W ngbnnxw Nupwards fit ~, 5 7117314110 +1, flgsy‘m‘i I) A (c)3.47X104NdownwaIds 1,11%th) (d)386X104NupwaIds WMSIMQO I g] _ I Fo (e)3.27X104Ndownwards ”A: lint + UM m l1 ‘ fifiv wt 1‘44er a 9 L "L p Phsxl 14-sp07—Exam 531, Page 1 of3 W 11 April 2007 CODE # 1 1:00 pm. — 1:50 pm. 5. A uniform beam, AB, of mass, m = 32.0 kg. is supported by a hinge on a wall at A and a cable at B, as shown. The cable makes an angle, 0 = 34.20 with 316% horizontal. The tension, FT, in the cable 15 unmimmH/z W¢w0m= (a)179N Z”? , L1; 6049» iii”; fit/“40:0 F 0‘ .FT “”31”“ ”10404, 31 INF SW8=E W m M 151N I LM A E W19E§;262N3F,.%M .4111, flag; W113 :=?(e)279N ijQ lam/119 IL? L 6. A uniform flag pole, PQ, of mass, m = 6.72 kg, is supported by a holder at P and a horizontal cable attached to Q and to the wall at R, as sho .- The angle, (0 = 2.70. The tension in the cable is F (2 ‘3 % T 51712 NW W" mm W 3524, R W‘Efiiigfi 21”,, : -15 i113 5100 + 111—0179 =0 19%st ‘5}, 13313331 WW4? = Limi‘m =71!“ .. 1 mam Pi ' L ‘f * - 6711171,} :?(e)43.2N :7 FT : 71923000 6 NW, . 5W<9~M¢ 7. A body of density, p = 2.71 x 103 kg/m3, has a volume of 6.72 x 10'3 m3. The mass of this body is (MW/1 (a) 19.2 kg m :7 V Wiid— (b>18.2kg P (c) 18.7 kg (d) 17.9 kg (e) 195 kg 8. A person of mass, M = 47.6 kg, rides a unicycle of mass, In = 16.2 kg on a horizontal surface. The gauge pressure in the tire is 2.52 X 105 N/m . The area of the tire in contact with the horizontal surfaceis MN W 0/1 gmlllTQ/W ¢W(lbm/M’Li L (a)3.07X10’:m: {1:3 : Fpsfiro £1 ’rp : fi[email protected]+l1)¢ ) x, g I} (b)2.48X10' . , 1 00, 71112.2mo-32; 01111001 (771017 mime/Mame; T f W) (d)2.59X10‘ , v z = W2/Q—Q(e)2.35X10'3$2 PM M 0 A g F GP A g P: 01 9. In a water barometer the water column was measured to have a height of h = 9.73 m. The atmospheric pressure at this time was P l :0 (a) 9.73x104N/m2 PR '7 Pl ‘Wflb " 0 WM z/ng (b) 1.04 x 105N/m2 Wt.) $(c) 9.54 X104N/m2 A (d) 1.02 x105 N/m2 WM #0:) 1.00 x105 N/m2 PA Phsxl 14-sp07—Exam 5_c1, Page 2 of 3 W 11 April 2007 CODE # 1 1:00 pm. — 1:50 pm. 10. A block of ice, of depth, d = 0.231 m, and density, pine = 0.918 X 103 kg/ma, floats in water. The height, h, of the top of the block above water is Ut AAA AA A :vA. 21A AAWW W 17 Efiiézi‘éééi‘é .. AMA Wfl‘my mm m Whh—wcussxw m [fit FA FAN?) :) 19 A}, AA? (d)2.:47x1o m qWWAW fir yA/LEW [W19 , ~ m1?» AVAAA AAAWAWAAAAA A AA 11. Abody of weight W= 78.3Nin air, is found to haveanapparent weight, W’ =56. when fully FT “w m} 1mm d water.T volume fthisb i ()1:ex:'33 6 AAA M3 S [A‘MM/AflWWM/MZ‘A lL/L Lit}: a m3 mllt-é/r(b)l.78X103m3 F FT fag; Ff film W i WW” W? at (0198x103ij pm W 1V0 (WW/A WWW ‘8% WWW F—’~.w‘ Wl,}=><d)2zsxw :11ij F5- 594)qu wwamnA/A ” (e)2.'341X10 m . J _u}= \/ AMA/“Q wflA’vk:WF—=W iW flA/fifiv W W 12 A very wide water tower of depth, h, is completely filled with water. There IS a small hate in 6 bottom of the tank from whlch water leaks. Water flows out of this hole with a speed, v= 9. 77 m/s. 8 FOL M AAA) ::H:,:fh%m AAA/1mm MWMM AAA LAC? [:9 333.21% MAW/CLAIM” P+Jcpu+pfl<mt 1L 'AFA 11/0 (Ml/M 1:333: :11 +‘L/JV may}, - in :M +£ng o A 53%;: 2M ®JL+PhtA+Ml+ L- TA :» pfigfiifipwfi 9 AL W 4, 015% WW?“ [ff/ff (AA AA) AMA? AAA W010“ AAUAW OKWWW) 17W WADMEWA/rowffiw Fig W Aim W l/AA AA AA. Mg m (AA AMA :AAAAAAA (AAAAAAAAA "1 led’a“ [014/de It) ,2) 4&4; Pia/d! +flq/h’ =3 0UP” ”M flwh :\ A MEAN/144.) Phsxl l4-spO7—Exam 5_cl, Page 3 of 3 ...
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