PHYS227N S13 COOK Quiz 2

# PHYS227N S13 COOK Quiz 2 - C Physics 227N/232N Spring 2013...

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Unformatted text preview: C Physics 227N/232N Spring 2013 Qui22—31January 2013 CM Name: . Group: E \ I will uphold the Honor Code: /_ 1) Calculate the magnitude auu direction of the electric field at point P in the figure 3 g. below, due to the 3 point charges. Let q= 100.00 uC and a = 2.00 m. A 5' la ? \4 z ’A * C r ‘5 J ¥4Paw+ E VL .--"‘\’ éiﬁ ( 1%}; +ql MM . .gq‘yxio“ C: [COMO QC 4 walO C 4 iDOX‘O'qé; Mfr ,x' man“; (2701' 'P , vs \l‘i A f 7 ‘1QQ 'ﬁ? V il- C’ W 2) If the two ”+q” charges are replaced with ”-q” charges, while the ”+2.0q” charge @mains the same, the electric field at point P will a) be one quarter its original value Explain your answer: b) be one half its original value %\ “GU“ equcdl O +0c‘elher ) remain unchanged (MUVO-m 3) double quadruple ther 3) A flat rectangular sheet of aluminum has sides of length 0.500 m and 0.300 m. It is _ 0 3’0 placed completely in a uniform electric field of magnitude 93.0 N/C. Calculate the 0‘ Y‘ 32:80 electric flux passing through the aluminum sheet under the following conditions. .- 0. \S'm‘ (a) The surface of the sheet is perpendicular to the electric field direction. 3 o‘g-ONic 5A db) The surface of the sheet is at 30° to the electric field. ﬂ ‘a.____.—--P""__ (O (c) The surface of the sheet is parallel to the electric field. 0 N/Q’IJV (d) If only 30% of the aluminum sheet was in the electric field what now would be —0 the answer to part (b)? ...
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