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Unformatted text preview: OLD DOMINION UNIVERSITY PHYSICS 227N/232N, Universiﬂ Physics
Spring 2013 Second Examination 10:00 am — 10:50 am Friday 15 February 2013
Room 142144, OCNPS PROFESSOR: Dr. D. C. Cook Answer 2 question: All answers should be on the examination paper.
If more space is required, attach sheets to paper. Text book may not be used.
This examination will be 5% of the total co rse sses ment. TABLE # V
Um! Honor Pledge Signatur Candidate's Name
CONSTANTS AND E UATIONS
so = 8.8510'12 c2 N" m2 lnC =10'9 c 111C =10'6 C k = l/41r80 = 9.0 109 N m2 C'2 F. = (k qlqz/rz) 1* F. = E q E = (k q1 /r2) r UE = k qlqz /r UE = Vq E = V/d V = k q2 /r E = (k q1 /r2) 1‘ Area of Circle A= m2 @E = I E.dS = q/so Surface area of a sphere AS = 4an Volume of a sphere V= 4/3 (at3 ) lei 1. Electric Flux (Total 50 Marks) la. A ﬂat sheet is in the shape of a rectangle with sides of length 0.400 m and
0.600 m. The sheet is immersed in a uniform electric ﬁeld of magnitude 75.0 N/C
that is directed at 200 from the plane of the sheet as shown in Figure 1. Find the magnitude of the electric ﬂux passing through the sheet. (10 Marks) 9’ awry“ o‘OOOW‘ “ 01“" IE: ’46 .QN/C go 3% 1,107
'L / —.— 2‘5’. Laglec,
d; aiw‘SUSWIWG
= (a , \Lo Elle:  c... ........ m. ANSWER: Lo. Ko W“ /c [ lb. A wedge shaped object is completely enclosed inside a uniform electric ﬁeld
as shown in Figure 2. The electric ﬁeld has magnitude of E i 2.50 NC and travels
at right angles through the left side square side of the wedge having area A1 = 9.00
m2. The electric ﬁeld travels parallel to the rectangular base of the wedge having
area A3 = 12.00 m2 and also parallel to the two vertical triangular sides of the
wedge. The electric ﬁeld exits the sloped rectangular face of the wedge of area A2. V
2.8”
.. 7;
SnB g
0058 "' 3;: (i) Calculate the electric ﬂux through the square side of the wedge of area A1. V, Answer: Electric Flux = “’2’ Z'KNN’L /C I l (l: 95‘ (‘1.oow""(Z.€o We} = 223 “if w W C
(ii)Calculate the electric ﬂux through the rectangular base of the wedge of area A3' I L/ N :1 l U
K I "  Answer: Electric Flux= m/C.
0.
(iii) Calculate the electric ﬂux through the sloped rectangular face of the _,._«
wedge of area A2. 5
_ M ’7. '
Answer: Electric Flux F Ll (o . M /C
‘2‘ /
J 2 1" o (40 Marks)
h C036 = 6 a — J
h 7 7 r C. )3
‘6 d5 1’ n g 7 /
"~\ 0 @
“g: 975% = s 03% U9“ U6 End of Problem 1 (0'
#4 2. Gauss’ Law (Total 50 Marks)
A small solid conducting sphere with radius a is located inside and concentric with
a larger conducting spherical shell with inner radius b and outer radius c as shown in Figure 3. The inner solid W’s‘phere has charge of Q1 = 3Q, and the outer conducting spherical shell has a c arge of Q2 = +2Q.
Solid Sphere Spherical I
5"
a Figure 3. Complete the four parts (i): (iv) below. (i) Explairﬁvhere and what the/charge is located on the solid sphere. ANSWER \J'” QcQCJ become i‘r \S 0,. conducive . I W no N 2—) \LL’ Qt L U (4 Marks) (ii) Explain where and what the charge is located on the spherical shell. ANSWER
QC beam/JBC O gongém’m" (iii) Use Gauss's Law to ﬁnd the electric ﬁeld at any distance r, between 1' = 0
and r = inﬁnity, from the common center of the two spheres. The calculations should be for the following regions, 0<r<a, a<r<b, b<r<c, c<r<oo. After com letin our workin on Pa e 6, place your answers in the
appropriate spaces below. Explain answers with working or wriﬁen explanation.  I" u 'i E: U
ANSWER(O<r<a) C/ {V W W/ﬂhu‘cf‘ihz MgrlZs)Vz ANSWER (a<r<b) *'/%% ' w“ 0 0 (8Marks)
ANSWER (b <r<c) O 0/ Lt (8Marks) ANSWER (c < r < oo) ( C3} (2‘ (8 Marks) (iv) Sketch the graph of Electric ﬁeld on the axes below for 0<r<oo. (6 marks)
EU) Space for Working Problem 2. End of Problem 2 END EXAM 2 ...
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 Spring '14
 ALEXANDERL.GODUNOV
 Physics

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