Analysis of an Unknown Bottle Calculations

# Analysis of an Unknown Bottle Calculations - 1.91 x 10^-3...

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Calculations: 1. Average of the volume of EDTA – 24.50 + 26.00 + 23.00 = 73.50 / 3 = 24.5 Volume of EDTA used (mL) = V(rough) = Vf – Vi / 50 mL – 27 mL = 23 mL 2. Calculate the number of moles of EDTA solution required to titrate the water sample: Formula = Average titration volume (liters) X Concentration of EDTA = Number of moles of EDTA Formula = 24.5 mL (convert mL = L; 24.5 / 1000) Formula = 0.0245 L x 1.91 x 10^-3 M Number of moles of EDTA = 0.000046795 = 4.68e^-5 3. Determine the number of moles of Ca2+ present in the bottled water sample: Ca 2+  + H 2 EDTA 2-    CaEDTA 2-  + 2H +   1 mole Ca2+ reacts with 1 mole EDTA so 1.91 x 10^-3 moles of EDTA reacts with    1.91 x 10^-3 moles of Ca2+ 4. Determine the number of moles of CaCO3 present in the bottled water, assuming all the Ca2+ combine with CO32-. 1 mole CaCO3+ reacts with 1 mole EDTA so 1.91 x 10^-3 moles of EDTA reacts     with

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Unformatted text preview: 1.91 x 10^-3 moles of CaCO3 5. Calculate the number of grams of CaCO3 present and convert it to mg. Number of grams = Molar Mass of CaCO3 x Number of moles of CaCO3 Number of grams = 100.0869 g/mol x 1.91 x 10^-3 Number of grams = 0.191165979 Convert grams to mg = 0.191165979 x 1000 = 191. mg 6. Calculate the number of mL of bottled water used in each titration to Liters. [Convert mL = L; 25.00 Ml / 1000 = 0.025 L ] 7. Calculate the ppm CaCO3 = mg CaCO3/Liters of H2O used ppm = 191 mg CaCO3 / 0.025 L of H2O used ppm = 7647 = 7.65e^3 8. Identify the brand of bottled water given: ppm = 7647 / 1,000,000 = 0.007647 g/mL Weight/volume percentage concentration (w/v %) = 0.191165979 g / 25 mL = 0.007647 g/mL (Tahoma)...
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