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Unformatted text preview: 1.91 x 10^3 moles of CaCO3 5. Calculate the number of grams of CaCO3 present and convert it to mg. Number of grams = Molar Mass of CaCO3 x Number of moles of CaCO3 Number of grams = 100.0869 g/mol x 1.91 x 10^3 Number of grams = 0.191165979 Convert grams to mg = 0.191165979 x 1000 = 191. mg 6. Calculate the number of mL of bottled water used in each titration to Liters. [Convert mL = L; 25.00 Ml / 1000 = 0.025 L ] 7. Calculate the ppm CaCO3 = mg CaCO3/Liters of H2O used ppm = 191 mg CaCO3 / 0.025 L of H2O used ppm = 7647 = 7.65e^3 8. Identify the brand of bottled water given: ppm = 7647 / 1,000,000 = 0.007647 g/mL Weight/volume percentage concentration (w/v %) = 0.191165979 g / 25 mL = 0.007647 g/mL (Tahoma)...
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 Spring '08
 Spitzer,S
 Mole, Litre

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