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Unformatted text preview: y = 0.002x - 0.0004 y = 0.002(4.0) - 0.0004 y=0.0076 D5. In the excel template, graph Vi vs Dilution for all Dilutions. Make note of any outliers, and discuss how to proceed with Grad TA. Include R-squared (3 pts.) (Shown on graph) D6. Determine the enzyme activity for the reaction. Activity = Product produced / time / volume. Include proper units! (2 pts.) Activity = Product produced / time / volume Activity = 1.90 mol/4 min/5 mL Activity = 0.095 or 0.1 mol/min-1/ml-1 D7. Determine the enzyme activity in the undiluted potato extract. Average the different values for all 4 dilutions. (2 pts)NOTE: The values for each dilution should be very similar and are measured per unit volume (ie, mmol/min/ml) Activity = 1.90 mol / (rate of reaction x volume) Activity = 1.90 mol / (0.0006 m/s x 5 mL) Activity = 3.17 mmol/min/ml Average: 3.1700 mmol/min/ml + 16.5000 mmol/min/ml + 1.8900 mmol/min/ml + 31.7000 mmol/min/ml / 4 = 13.2000 mmol/min/ml D8. Convert activity /volume to activity /weight (2 pts) 13.2 / (1/13.2) / 3750 = 0.05 mmol/min/mL...
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- Spring '08
- 1 pt, 3 pts, 0.0006 m/s, 0.0061 mM, 0.11 mM