This
** preview**
has intentionally

**sections.**

*blurred***to view the full version.**

*Sign up*
**Unformatted text preview: **Chapter 6 Question 95 H = L – (Lcos(20)) Assume no air resistance 0 = Delta K + Delta U 0= (.5)(m)(v sub f ^2) – (.5)(m)(v sub i ^2) + 0 – mgh Vf ^2 = (vi ^2) + (2gh) 2[0= (.5)(m)(v sub f ^2) – (.5)(m)(v sub I ^2) – mgh 0= mf sub f ^2 – mv sub I ^2 = 2mgh ESCAPE SPEED (.5)(m)(v sub I ^2) - G*m * m sub e R sub e V sub I = ? square root of ((2G* m sub e)/(R sub e)) V sub I = 11.2 km/s Power = mg delta y over delta t M Mg(820m) all over 20 min 1 min over 60 seconds Power = 75 kg *9.8 m/s^2 * 820 m all over 60 seconds =500 N...

View
Full
Document