Physics Notes 09-24-07

# Physics Notes 09-24-07 - Chapter 6 Question 95 H = L...

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Physics Notes 9-24-07 W=work= F sub x * delta x Work is a number W (due to gravity) = (9.81 ^2) * Mass W (due to gravity) = (mg)*Delta y W (non conservative forces) = Delta K + Delta U SLIDE 3 What is the velocity given h, theta, and mew sub k? Mass/gravity force facing straight down, tilted normal force, and tilted frictional force. W (non conservative) = Delta K + Delta U W = (.5)(m)(v^2) + (0 – mgh) [F sub f = mew sub k * N = mew sub k * mg cos theta] Distance down ramp = h/sin theta W = (mew sub k mg cos theta)(h divided by sin theta) W= mew sub k * mg * cot(theta) *h -mew sub k * mg * cot(theta) *h = (.5)(M)(V^2) – (MGH) Isolate for v = square root of (2gh(1- mew sub k * cotangent(theta)))

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Unformatted text preview: Chapter 6 Question 95 H = L – (Lcos(20)) Assume no air resistance 0 = Delta K + Delta U 0= (.5)(m)(v sub f ^2) – (.5)(m)(v sub i ^2) + 0 – mgh Vf ^2 = (vi ^2) + (2gh) 2[0= (.5)(m)(v sub f ^2) – (.5)(m)(v sub I ^2) – mgh 0= mf sub f ^2 – mv sub I ^2 = 2mgh ESCAPE SPEED (.5)(m)(v sub I ^2) - G*m * m sub e R sub e V sub I = ? square root of ((2G* m sub e)/(R sub e)) V sub I = 11.2 km/s Power = mg delta y over delta t M Mg(820m) all over 20 min 1 min over 60 seconds Power = 75 kg *9.8 m/s^2 * 820 m all over 60 seconds =500 N...
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## This note was uploaded on 04/15/2008 for the course PHY 101 taught by Professor Schwarz during the Spring '08 term at Syracuse.

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Physics Notes 09-24-07 - Chapter 6 Question 95 H = L...

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