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Unformatted text preview: negative free charge on the other plate, the third is due to the positive induced charge on one dielectric surface, and the fourth is due to the negative induced charge on the other dielectric surface. Note that the field due to the induced charge is opposite the field due to the free charge, so the fields tend to cancel. The induced charge is therefore q i = q f AE = 5 . 10 9 C (8 . 85 10 12 F / m)(100 10 4 m 2 )(1 . 10 4 V / m) = 4 . 1 10 9 C = 4 . 1 nC ....
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- Spring '08