Unformatted text preview: πni sol = 6 . 00 A 2 π (10 . × 10 2 m − 1 )(20 . × 10 − 3 A) = 4 . 77 × 10 − 2 m = 4 . 77 cm . This distance is less than the radius of the solenoid, so the point is indeed inside as we assumed. (b) The magnitude of the either field at the point is B sol = B wire = µ ni sol = (4 π × 10 − 7 T · m / A)(10 . × 10 2 m − 1 )(20 . × 10 − 3 A) = 2 . 51 × 10 − 5 T . Each of the two fields is a vector component of the net field, so the magnitude of the net field is the square root of the sum of the squares of the individual fields: B = ± 2(2 . 51 × 10 − 5 T) 2 = 3 . 55 × 10 − 5 T....
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 Spring '08
 Reich
 Magnetic Field, Complex number, net field, solenoid axis, iwire /2r

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