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Unformatted text preview: t = 0, just after the switch is closed. Now, just after the switch is closed, the inductor prevents the rapid buildup of current in its branch, so at that time, i 2 = 0 and i 1 = i . Thus i = i , so i 1 = ie Rt/L and i 2 = i i 1 = i 1 e Rt/L . (b) When i 2 = i 1 , e Rt/L = 1 e Rt/L , so e Rt/L = 1 2 . Take the natural logarithm of both sides and use ln(1 / 2) = ln 2 to obtain ( Rt/L ) = ln 2 or t = L R ln 2 ....
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 Spring '08
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