graded hw 5 - GradingSummary ,and ,are inthe\"Details\"sectionbelow DateTaken TimeSpent PointsReceived QuestionType 1Days,8h

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Unformatted text preview: 1/15/2015 Student Gradebook Exam Grading Summary These are the automatically computed results of your exam. Grades for essay questions, and comments from your instructor, are in the "Details" section below. Date Taken: Time Spent: Points Received: Question Type: 12/5/2014 1 Days , 8 h , 56 min , 47 secs 21 / 25 (84%) # Of Questions: Essay # Correct: 7 N/A Grade Details ­ All Questions Show the value of the register and the carry after the execution of the ASLA instruction. Given the original content 0 1 0 0 1 0 1 0 of Register A and C carry flag 1. Question : 1 C = Register A = Student Answer: ASLA = Arithmetic shift Left A (ASRA) C = 1 Register A = 00101010 Instructor Explanation: Show the new values after executing: ASLA. Points Received: 1 C 0 0 1 0 1 0 1 0 3 of 3 Comments: Show the value of the register and the carry after the execution of the LSLB instruction. Given the original content 0 1 0 0 1 0 1 0 of Register B and C carry flag 2. Question : 1 C = Register A = Student Answer: Instructor Explanation: Points Received: LSLB = Logic Shift Left B C = 1 Register B = 00101010 Show the new values after executing LSLB. 1 C 0 0 1 0 1 0 1 0 Comments: 3. Question : 3 of 3 Show the value of the register and the carry after the execution of the ASRB instruction. (NEXT(c3330f954a))/Main/CourseMode/StudentGradebookExam/StudentGradebookExamView.ed?courseItemSubId=5734… 1/3 1/15/2015 Student Gradebook Exam Given the original content of Register B and carry flag 1 0 1 0 0 1 0 1 0 C C = Register A = Student Answer: ASRB = Arithmetic Shift Right B Register B = 11010010 C = 1 Instructor Explanation: Show the new values after executing: ASRB. Points Received: 1 1 0 1 0 0 1 0 1 C 3 of 3 Comments: Show the value of the register and the carry after the execution of the RORA instruction. Given the original content 1 1 0 1 1 1 1 1 of Register A and C carry flag 4. Question : 0 C = Register A = Student Answer: Instructor Explanation: RORA = Rotate Right A C = 0 Register A = 11011111 Show the new values after executing RORA. Points Received: 0 C 1 1 0 1 1 1 1 1 3 of 3 Comments: Show how to perform 77 x 34 in the HCS12. Store the result in a WORD­size variable called var1. 5. Question : Student Answer: Instructor Explanation: LDAA #77 INLUDE 'derivative' ORG $2000 DS.B Var1 #77,#34 LDAA #77 LDAB #34 EMUL STAB Var1 LDAB #34 MUL STD var1 Points Received: 4 of 4 Comments: Show how to perform 77 / 3 in the HCS12. Store the quotient in a WORD­size variable called result, and the remainder in a WORD­size variable called remainder. 6. Question : Student Answer: Instructor Explanation: LDD #77 INLUDE 'derivative' ORG $2000 DS.B remainder #77,#3 LDD #77 LDX #3 IDIV STX remainder (NEXT(c3330f954a))/Main/CourseMode/StudentGradebookExam/StudentGradebookExamView.ed?courseItemSubId=5734… 2/3 1/15/2015 Student Gradebook Exam LDX #3 IDIV STY result STD remainder Points Received: 3 of 4 Comments: STD remainder 7. Question : How are the following decimal­signed numbers represented in HCS12? I. ­12 II. +127 III. ­128 I. 12 in binary = 1100 1's complement = 0011 2's complement = 0011 + 1 = 0100 2's complement of a number = the negative value ­12 = 0100 II. +127 in binary = 11111111 II. 128 in binary = 10000000 1's complement = 01111111 2's complement = 01111111 + 1 = 10000000 2's complement of a number = the negative value ­128 = 10000000 Student Answer: Instructor Explanation: I. 11110100 II. 01111111 III. 10000000 Points Received: 2 of 5 Comments: * Times are displayed in (GMT­07:00) Mountain Time (US & Canada) (NEXT(c3330f954a))/Main/CourseMode/StudentGradebookExam/StudentGradebookExamView.ed?courseItemSubId=5734… 3/3 ...
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