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Final_Exam_f05_v5_Solutions

Final_Exam_f05_v5_Solutions - Physics 112 Final Exam...

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Physics 112 — Final Exam Solutions Fall 2005 1. (a) 8.0 cm (b ) ω = 2 π /T = 2 π /(2.0 s) = π s -1 (c) Q = π ( τ /T) = π (12 s/2.0 s) = 6 π = 19 2. (a) (b) [+3 for any one of the possible methods for each case, -1 for bad or missing labels] 3. (a) E (b) B (c) G (d) C 4. (a) B (b) B (c) F 5. (a) C (b) D 6. (a) H (b) N [+3 for N; +1 for G, H, J, K, L, or M] 7. G 8. (a) or (b) Σ F y = f - mg = ma y = 0 f = mg f 2 + N 2 = (mg) 2 + N 2 = 2mg N = 3 mg f μ s N mg μ s 3 mg (c) Σ F x = ma x N = m v 2 R μ s 1/ 3 = 0.58 v = NR m = 3 mgR m = 3 gR = 1.32 gR 9. (a) (b) About axle: Σ τ = 0 = Mg(0.40 m) - m p g(0.60 m) - N(1.60 m) - Tsin60°(1.60 m) = 0 with N = mg (ball) T = Mg(0.40 m) - m p g(0.60 m) - mg(1.60 m) (1.60 m)sin60° = (20 kg)(0.40 m) - (2.0 kg)(0.60 m) - (0.50 kg)(1.60 m) (1.60 m)(0.866) (9.8 m/s 2 ) = 42.4 N (c) I axle = (20 kg)(0.40 m) 2 + 1 12 (2.0 kg)(2.00 m) 2 + (2.0 kg)(0.60 m) 2 = 4.59 kg-m 2 p 1f p 1 ! p 1 ! p 1i - p 1i p 1i p 2i p 1i p 2i p i ! p i ! p i ! w or mg N f Earth Sphere or Wall Sphere or Wall w or mg Earth Sphere or Wall F contact Mg Earth m g pole Earth F Axle T String N Ball
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(d) Cons. of Energy: 0 = - Mg(0.40 m) + m p g(0.60 m) + mg(1.60 m) + 1 2 (mr 2 + I) ω 2 ω 2 = 2 Mg(0.40 m) - m p g(0.60 m) - mg(1.60 m) mr 2 + I = 2 (20 kg)(0.40 m) - (2.0 kg)(0.60 m) - (0.50 kg)(1.60 m) (0.50 kg)(1.60 m)
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