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s
d
Solutions: Prelim 1, Spring 2006
1.(a) A; (b) A; (c) A
2. F=0.18N
3.(a) C; (b) C; (c) B
4. (a) W=5 N; (b) W=40 N
5. (a) D; (b) E; (c) C; (d) F; (e) A
6. (a) F=500N; (b) v=30 m/s; (c) v=15 m/s
7. (a)
so
(b) t
BI
> t
IB
: You have a headwind
from Boston to Ithaca.
(c) v
ave
< v
737
: Your land speed is less than your airspeed because
you have to fly into the wind to go straight to your destination.
(d) v
ave
< v
737
: You have a headwind for more time than you have
a tailwind.
8. An equivalent configuration is shown below with
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Unformatted text preview: (1/k 1 )=(1/k)+1/(2k)=3/(2k) (1/k 2 )=(1/k)+(1/k)=2/k Combining these in parallel gives K eff =k 1 +k 2 =(5/6)k=83.3 N/m 9. (a) (b) (c) Solving for t, and substituting into the equation for x gives 10.(a) (b) None (c) (d) Use coordinate system parallel and perp to wedge, We then use that the two tensions are equal and the two accelerations are equal, to find θ φ v 737 v wind V ground F F K 1 K 2 T W Before W After...
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This note was uploaded on 02/14/2008 for the course PHYS 1112 taught by Professor Leclair,a during the Spring '07 term at Cornell University (Engineering School).
 Spring '07
 LECLAIR,A

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