Hour Exam 3 2013 - HOUR EXAM 3 Chemistry 030.102 Section 1...

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Page 1 of 10HOUR EXAM 3NAME (Print clearly)______________________________Chemistry 030.102Last nameFirst nameSection 1 – Prof. DagdigianApril 26, 2013jhed ID__________________BE SURE TO PUT YOURNAME ON THE LAST PAGECalculators allowed, but do not use programmable features.One sheet of 8½×11 in. paper with notes may be brought into the exam.Miscellaneous information:Speed of lightc= 3.00×108m s–1Avogadro's numberN0= 6.02×1023mol–1Planck's constanth= 6.63×10–34J sElectron chargee= 1.60×10–19CParticle in a box energiesEn=n2h2/(8mL2)Electron massme= 9.11×10–31kgBohr radiusa0= 5.29×10–11mProton massmp= 1.67×10–27kgPlanck's formulaE=hνde Broglie's relation:λ=h/p1 Joule = 1 kg m2s–21 eV = 1.602×10–19JHeisenberg uncertainty relation:(Δx)(Δp)h/4πPermittivity of vacuumε0= 8.85×10–12C2J–1m–1Energies in one-electron atomsEn= –(2.18×10–18J)Z2/n2Relationship of light frequency and wavelength:νλ=cBeer-Lambert law (base 10):–log10[IS/IR] =A=εClFirst five rows of the periodic tableHHeLiBeBCNOFNeNaMgAlSiPSClArKCaScTiVCrMn FeCoNiCuZnGaGeAsSeBrKrRbSrYZrNbMoTcRuRhPdAgCdInSnSbTeIXeAtomic numbers of the inert gases:He2Ne10Ar18Kr36Xe54Rn86You may use the space below or on page 9 for calculations, etc.
Page 2 of 101.Orbital Correlation Diagram for Second-Row Diatomic MoleculesOne of the oxides of nitrogen is the diatomic molecule nitric oxide (NO).This molecule is a by-product of combustion in air and is an important signaling molecule in mammals.(a)Draw the molecular orbital correlation diagram for NO.Please note that the ordering of theorbitals is similar to that of the O2molecule.

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