problem01_90

problem01_90 - 1.90 From Eq(1.27 the cross product is ^...

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1.90: From Eq. (1.27), the cross product is . ˆ 00 . 13 00 . 11 ˆ 00 . 13 00 . 6 ˆ ) 00 . 1 ( 13 ˆ ) 00 . 11 ( ˆ ) 00 . 6 ( ˆ ) 00 . 13 ( - + - = - + + - k j i k j i The magnitude of the vector in square brackets is , 93 . 1 and so a unit vector in this direction (which is necessarily perpendicular to both ) and B A is - + - 93 . 1
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This homework help was uploaded on 02/14/2008 for the course PHYS 112 taught by Professor Wheeler during the Spring '08 term at Cornell.

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